Using the Hardy-Weinberg equation, if p = 0.23, what must q equal?

A question could look like: If $mathbf98$ out of $mathbf200$ individuals in a population express the recessive phenotype, what percent of the population would you predict would be heterozygotes?...

The Hardy-Weinberg principle states that in a large randomly breeding population, the frequency of alleles will remain the same from generation to generation, as long as certain assumptions are met....

The Hardy-Weinberg equilibrium assumes the following characteristics: organisms are diploid. only occurs. generations are non overlapping. mating is random. population size is infinitely large. allele frequencies are equal in...

In the Hardy-Weinberg equilibrium equation ($p^2 + 2pq + q^2 = 1$), the term $2pq$ represents the genotype frequency of heterozygotes (Aa) in a population in equilibrium. The term $p^2$...

The Hardy-Weinberg equation is: $p^2 + 2pq + q^2 = 1" "$ and also $" "p+q=1$ where $p^2$ is the percentage of homozygous dominant phenotype where...

Hardy Weinberg law gives the idea when there is no evolution or we can say that population remains in equilibrium. P + Q = 1 $P^2$ + 2PQ +...

Hardy Weinberg principle is variously known as HW law/theorem. Population geneticists term it as HW equilibrium. According to this, the frequencies of different alleles of a gene will remain constant...

The Hardy-Weinberg principle states that both allele and genotype frequencies will remain the same in successive generations of a growing population if (i) mating is random; (ii) no occur; (iii)...

For the first part of your question read this and the other links that the answer provides. And the following will give you an idea about the practical use...

The is $p^2+2pq+q^2=1$ where $p$ is the frequency of allele A $q$ is the frequency of allele a $p^2$ is the frequency of individuals with AA $2pq$ is the frequency...