Given the following information, how would you determine the allele frequencies for the B allele and the b allele? How would you determine the genotype frequencies for the BB, Bb, and bb genotypes?

In presence of dominant allele the recessive character can not be expressed, i.e. masked. When recessive allele is present in double dose, only then the recessive character is expressed.

The parental diploid genotypes, such as $"TT"$ and $"Tt"$ will be separated into haploid gametes during . So the parent with the genotype $"TT"$ can only pass on the $"T"$...

Since ais is whylbinism is a recessive trait, then it does not show unless it is homozygous in the individual, and this is why the kid is aa. Since the...

Alleles are often represented by upper and lower case letters. The upper case letters represent the dominant form while the lower case letters represent the recessive form. The combination...

Genotype: $"RRTt"$ For this plant, the genotype for leaf color is $"RR"$, which is homozygous dominant, consisting of two dominant alleles. Since the only allele possible is dominant, the plant...

Assuming conditions are met, we will use the $"Hardy-Weinberg equation"$ which is: $p^2+2pq+q^2=1$ Where: $p^2 = "frequency of homozygous dominant genotype"$ $2pq = "frequency of heterozygous genotype"$ $q^2 =...

The Hardy-Weinberg equation is: $p^2 + 2pq + q^2 = 1" "$ and also $" "p+q=1$ where $p^2$ is the percentage of homozygous dominant phenotype where...

You answer this by using Hardy-Weinberg Equation. From the $1000$ individuals, we know that $510$ show dominant phenotype but we don't know how many of those individuals are homozygous dominant...

You'll need to understand the , but you don't even need to use it to answer this question. $p^2 + 2pq + q^2$ = 1 Let's re-write Hardy Weinberg using...

We use the Hardy-Weinberg equation, which states that, $p^2+2pq+q^2=1$ where: $p^2 $is the frequency of the homozygous genotype $"AA"$ $2pq$ is the frequency of the...