Magnesium reacts with HCl to produce MgCl2 and hydrogen gas. How many liters of a 1.85 M HCl solution completely react with 4.00 grams of magnesium? Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)

Given Moles of Mgo is 0.15 moles . Mg react with O2 and form MgO .2 mole of Mg gives 2 mole of Mgo .So 0.15 moles of Mg Gives...

Solution:The balanced chemical equation:2Mg + O2 → 2MgOAccording to the chemical equation: n(Mg)/2 = n(O2) = n(MgO)/2Molar mass of Mg is 24 g/mol.Moles of Mg = 10.8 g × (1...

As HCl is in excess, Mg will be the limiting reagent for this reaction.n = m/MM(Mg)=24.3 g/moln (Mg) = 6.20/24.3 = 0.3 moln (H2)=n (Mg) = 0.3 moln (H2) =...

The balanced chemical eqiation is N2(g)+3H2(g)→2NH3(g) The mass of nitrogen is m(N2) = 3.40 g The amount of nitrogen is n(N2) = m(N2)/M(N2[]/sub) = 3.4/28.013 = 0.121 mol The reacion...

Solution: ν(H2)=10.4/2=5.2 mol 3 mol H2→2 mol NH3, so ν(NH3)=(5.2/3)*2=3.47 mol m(NH3)=17*3.47-=58.99 g Answer: 58.99 grams of NH3.

0.2 g

Zn+2HCl=ZnCl2+H20.063/65=0.000969230769 moles.V=nRT/p= 0.000969230769 x 0.082 x 298 / 0.98 = 0.0241674726 L.

According to the equation 1L of CH4 reacts with 2L of O2. Volume of O2 = V(CH4) *2 = 56*2 = 112 L

Solution:A chemical equation must be balanced:N2 + 3H2 = 2NH3According to the reaction equation for 3 mol of H2 is needed 1 moles of N2.Therefore, mass of H2 = V...

74.4 g of hydrogen chloride were used in the reaction.