Nitrogen gas reacts with hydrogen gas to produce ammonia. N2(g)+3H2(g)→2NH3(g) How many grams of H2 are needed to react with 3.40 g of N2? Thanks for your help!!

Md Ariful Islam

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The balanced chemical eqiation is N2(g)+3H2(g)→2NH3(g) The mass of nitrogen is m(N2) = 3.40 g The amount of nitrogen is n(N2) = m(N2)/M(N2[]/sub) = 3.4/28.013 = 0.121 mol The reacion stechiometry shows that we need 3 times more moles of hydrogen to react completely with this amount of nitrogen, or n(H[sub]2) = 3x0.121 = 0.363 mol The mass of hydrogen reqired is m(H2) = n(H2)M(H2) = 0.363x2.016 = 0.732 g Answer: 0.732 g
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