Calculate the number of liters of Hydrogen gas at STP that would be produced by the reaction of 6.20g of Magnesium with excess at HCl. Mg+2HCl➡️MgCl2+H2

Md Ariful Islam

0 like 0 dislike
1 views
Share with your friends

1 Answers

Md Ariful Islam

Call

As HCl is in excess, Mg will be the limiting reagent for this reaction.

n = m/M

M(Mg)=24.3 g/mol

n (Mg) = 6.20/24.3 = 0.3 mol

n (H2)=n (Mg) = 0.3 mol

n (H2) = V/22.4

V(H2) = n (H2) x 22.4 = 0.3 x 22.4 = 6.7 l

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
How many liters of hydrogen gas will be produced at STP by reacting with 1.71 L of 0.45 <i>M</i> HCl with excess zinc?

Volume of Hydrogen Gas;=2.29L

1 Answers 1 views
Calculate the enthalpy of the following reaction: 2Mg + O2 &gt; 2MgO Given: Mg + 2HCl &gt; MgCl2 + H2. H=-21.0 kJ MgO + 2HCl &gt; MgCl2 + H2O. H=-33.5 kJ H2 + 1/2 O2 &gt; H2O. H=-76.0 kJ

Enthalpy=(-21)2+(33.5)2-76-42+67-96-42-9=-51 =-51kJ

1 Answers 1 views
In a certain reaction 0.20g of hydrogen gas was combined with 3.20g of oxygen gas. find the molecular formular of the compound

Molar mass of Oxygen = 15.9993.2/15.999= 0.2Molar mass of hydrogen= 1.007840.2/1.00784=0.2= HO

1 Answers 1 views
Calculate the enthalpy of the following reaction: (3 marks) 2Mg + O2 → 2MgO Given: Mg + 2HCl → MgCl2 + H2 ΔH = -21.0 kJ MgO + 2HCl → MgCl2 + H2 O ΔH = -33.5 kJ H2 + ½ O2 → H2 O ΔH = -76.0 kJ

Solution:Given:(1) Mg + 2HCl → MgCl2 + H2, ΔH1 = -21.0 kJ(2) MgO + 2HCl → MgCl2 + H2O, ΔH2 = -33.5 kJ(3) H2 + ½O2 → H2O, ΔH3 =...

1 Answers 1 views
10.8 g of magnesium is combined with 10.0 liters of oxygen to form magnesium oxide. Calculate the mass (in grams) of magnesium oxide that will be produced. 2Mg + O2 2MgO

Solution:The balanced chemical equation:2Mg + O2 → 2MgOAccording to the chemical equation: n(Mg)/2 = n(O2) = n(MgO)/2Molar mass of Mg is 24 g/mol.Moles of Mg = 10.8 g × (1...

1 Answers 1 views
Net ionic equation for Cu(s) + 2HCl(aq) → CuCl2(aq) + H2(g) Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g) Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)

Cu(s) + 2HCl(aq) → CuCl2(aq) + H2(g) Cu(s) + 2H+(aq) → Cu2+(aq) + H2(g) ‒ net ionic equation Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g) Fe(s) + 2H+(aq) → Fe2+(aq)...

1 Answers 1 views
Identify the acid in the reaction 2HCl + Mg(OH)2 → MgCl2 + 2H2O. A. HCl B. Mg(OH)2 C. MgCl2 D. H2O E. None of the Above

A. HCl is acid because it donate H+

1 Answers 1 views
How many liter of hydrogen (H2) gas can be produced from the reaction of 0.750 g of Zinc (Zn) metal with excess HCl at STP. Zn(s)+2HCl(aq)—&gt;H2(g)+ZnCl2(aq)

Zn(s)+2HCl(aq)—&gt;H2(g)+ZnCl2(aq) 22.4 x 0.75 / 65 = 0.258461538 l (H2).

1 Answers 1 views
2HCl + Mg → MgCl2 + H2 If we use 12grams of HCl and 8grams of Mg, which is the limiting reactant, and which reactant is excess?

n(HCl) = m/M = 12g/36.5g/mol = 0.329 moln(Mg) = 8g/24g/mol = 0.333 molAccording to the equation 1 mol of Mg reacts with 2 mol of HCl. HCl is the limiting...

1 Answers 1 views
Magnesium reacts with HCl to produce MgCl2 and hydrogen gas. How many liters of a 1.85 M HCl solution completely react with 4.00 grams of magnesium? Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)

1 mole of Mg reacts with 2 moles of HCl24g of Mg reacts with 2 moles of HCl1g of Mg will react with 2/24 moles of HCl4g of Mg will...

1 Answers 1 views
X