1 Answers
Call
Talk Doctor Online in Bissoy App
If sodium hydroxide reacts with sulfuric acid write an equation to show why you will need 2 mol of NaOH for 1 mol of H2SO4
2NaOH + H2SO4 → Na2SO4 + 2H2O
1 Answers 1 views
<ol><li>What volume (mL) of 0.70 M Sodium hydroxide (NaOH) is needed to neutralize 270 mL of 0.40 M Sulfuric acid (H2SO4)? </li></ol>2 NaOH + H2SO4 Na2SO4 + 2 H2O
What volume (mL) of 0.70 M Sodium hydroxide (NaOH) is needed toneutralize 270 mL of 0.40 M Sulfuric acid (H2SO4)?2 NaOH + H2SO4 + Na2SO4 + 2 H20=NaOH is equal...
1 Answers 1 views
6. Calculate what volume of a sulfuric acid solution (specific gravity = 1.07; and containing 10.0 % H2SO4 by mass) contains 18.50 g of pure H2SO4 at a temperature of 25°C.
1.07 g/mL x ?# mL x 0.10 = 18.50 g.0.107ml=18.50g= 172.9ml
1 Answers 1 views
Determine the limiting reactant when 4.2 mol Fe(OH)3 reacts with 6.5 mol H2SO4 in the following reaction.
2 Fe(OH)3 + 3 H2SO4 --> Fe2(SO4)3 + 6 H2O
2 Fe(OH)3 + 3 H2SO4 --> Fe2(SO4)3 + 6 H2ONumbers of moles of each reactant must be devided by coefficients to find the limiting reactant:n(Fe(OH)3) = 4.2 mol / 2...
1 Answers 1 views
3.75M sulfuric acid solution that has a density of 1.23g/ml. Calculate the mass percent,molality and normality of sulfuric acid?H=1g/mol , O=16g/mol , S=32 g/mol
Solution:sulfuric acid = H2SO4The molar mass of H2SO4 = 2×Ar(H) + Ar(S) + 4×Ar(O) = 2×1 + 32 + 4×16 = 98 (g/mol).Suppose that the volume of the solution is...
1 Answers 1 views
From an initial mix of: 2 mol Cl2, 1 mol Br2, 0.5 mol I2, 0.5 mol Cl−, 1 mol Br−, 2 mol I−; the total quantity of I2 present after all possible reactions occur is
0.5 mol I2 and 0.5 mol Cl- will not react with anything; 2 mol I- will react with one mol of Cl2 producing one mol of I2: 2I- + Cl2...
1 Answers 1 views
what is the volume of a 0.16 M sulfuric acid (H2SO4) solution that contains 0.35 mol sulfuric acid?
C = 0.16 M n = 0.35 mol. V= c/n. V=0.35/0.16 = 2.22(liters) Answer: 2.22 liters.
1 Answers 1 views
Using 10 mL of 0.2 M H2SO4 solution, calculate the volume of water necessary to create a
0.05 M solution of H2SO4. What is the final volume of the solution?
CM= n/V.n=CM x V = 0.2 x 0.01 = 0.002 V=n/CM=0.002/0.05 = 0.04 L.∆V=40 - 10 = 30 ml of necessary of water.
1 Answers 1 views
A solution of sulfuric acid was made by dissolving 20 grams of 98 percent sulfuric acid in 250 ml of water. Express the concentration of this solution in percent by weight
98% sulphuric acid means in 100 g sulphuric acid source exact amount of sulphuric acid, H2SO4 present 98 g. So in 20 g, exact amount of H2SO4 present =...
1 Answers 1 views
a 25ml sample of dilute h2so4 is titrated with 0.0965m naoh so that both protons of h2so4 are neutralized it takes 17.83ml of base to reach end point what is the molarity of h2so4
Given,Volume of H2SO4, (V1) = 25mlStrength of NaOH = 0.0965 m For the titration purpose Normal strength of NaOH will usedSo,Normally of the NaOH = (0.0965×no. of OH– in 1...
1 Answers 1 views