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Calculate the mole fraction of H2SO4 in 8%(w/w) aqueous H2SO4 ( molar mass: 98 g/mol, 18g/mol respectively
8%(w/w) aqueous H2SO4 solution means that 100 g of solution contains 8 g of the acidMass of water: 100 – 8 = 92 (g)Moles of each: H2SO4: 8 g /...
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<ol><li>What volume of a 6.0 mol/L sulfuric acid solution would be required to make 500 mL of 0.24 mol/L sulfuric acid? </li></ol>
Molar Mass of sulfuric acid = 98.0796 × 98.079 = 588.4740.24 × 0.5 = 6.0 × X0.12= 6XX =0.12/6= 0.02L= 20ml.
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If sodium hydroxide reacts with sulfuric acid write an equation to show why you will need 2 mol of NaOH for 1 mol of H2SO4
2NaOH + H2SO4 → Na2SO4 + 2H2O
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<ol><li>What volume (mL) of 0.70 M Sodium hydroxide (NaOH) is needed to neutralize 270 mL of 0.40 M Sulfuric acid (H2SO4)? </li></ol>2 NaOH + H2SO4 Na2SO4 + 2 H2O
What volume (mL) of 0.70 M Sodium hydroxide (NaOH) is needed toneutralize 270 mL of 0.40 M Sulfuric acid (H2SO4)?2 NaOH + H2SO4 + Na2SO4 + 2 H20=NaOH is equal...
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6. Calculate what volume of a sulfuric acid solution (specific gravity = 1.07; and containing 10.0 % H2SO4 by mass) contains 18.50 g of pure H2SO4 at a temperature of 25°C.
1.07 g/mL x ?# mL x 0.10 = 18.50 g.0.107ml=18.50g= 172.9ml
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3.75M sulfuric acid solution that has a density of 1.23g/ml. Calculate the mass percent,molality and normality of sulfuric acid?H=1g/mol , O=16g/mol , S=32 g/mol
Solution:sulfuric acid = H2SO4The molar mass of H2SO4 = 2×Ar(H) + Ar(S) + 4×Ar(O) = 2×1 + 32 + 4×16 = 98 (g/mol).Suppose that the volume of the solution is...
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From an initial mix of: 2 mol Cl2, 1 mol Br2, 0.5 mol I2, 0.5 mol Cl−, 1 mol Br−, 2 mol I−; the total quantity of I2 present after all possible reactions occur is
0.5 mol I2 and 0.5 mol Cl- will not react with anything; 2 mol I- will react with one mol of Cl2 producing one mol of I2: 2I- + Cl2...
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What is the volume of a 0.19 M sulfuric acid (H2SO4) solution that contains 0.34 mol sulfuric acid?
The molarity can be defined as following:M = n / Vwhere M - molarity of the solution, n - number of moles of the solute, V - volume of the...
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Using 10 mL of 0.2 M H2SO4 solution, calculate the volume of water necessary to create a
0.05 M solution of H2SO4. What is the final volume of the solution?
CM= n/V.n=CM x V = 0.2 x 0.01 = 0.002 V=n/CM=0.002/0.05 = 0.04 L.∆V=40 - 10 = 30 ml of necessary of water.
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A solution of sulfuric acid was made by dissolving 20 grams of 98 percent sulfuric acid in 250 ml of water. Express the concentration of this solution in percent by weight
98% sulphuric acid means in 100 g sulphuric acid source exact amount of sulphuric acid, H2SO4 present 98 g. So in 20 g, exact amount of H2SO4 present =...
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