The partial pressure of Ch4(g) is 0.145 atm and that of O2(g) is 0.200 atm in a mixture of the two gases. What is the mole fraction of each gas in the mixture?

Md Ariful Islam

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Md Ariful Islam

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p_i/p_total =x_i=n_i/n_total , where x_i- mole fraction. x_(〖CH〗_4 )= (0.145 atm)/((0.145+0.200) atm)×100%=42.0%; x_(O_2 )=(0.200 atm)/((0.145+0.200) atm)×100%=58.0%. Answer: x_(〖CH〗_4 )=42.0%; x_(O_2 )=58.0%.
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