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If the total air pressure is 1.05 atm, the partial pressure of carbon dioxide is 0.08 atm, and the partial pressure of hydrogen sulfide is 0.05 atm, what is the partial pressure of the remaining air?
As we know, Total pressure is the sum of partial pressure of individual gases.PT = 1.05 -(0.08+0.05+Pair)Pair = [0.92] atm
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A mixture of 90.0 grams of CH4 and 10.0 grams of argon has a pressure of 250 torr under conditions of constant temperature and volume. The partial pressure of CH4 in torr is:
Molar mass of CH4 = 16.04 g/molMolar mass of argon = 39.9g/molFrom the given masses we can calculate number of moles followed by mole fraction of each gas.Number of moles...
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At 1.00 bar and 0 °C, a 5.04 L mixture of methane (CH4) and propane (C3H8) was burned, producing 16.5 g of CO2. What was the mole fraction of each gas in the mixture? Assume complete combustion.
First, let's determine the total number of moles of both gases in the mixture at given conditions via Mendeleev-Clapeyron's law: PV=nRT; n=(PV)/(RT)= (101.3*10^3*5.04*10^-3)/(8.31*273)=0.225 mol. Then, let's write down to equations...
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A 10 gram mixture of C2H6 and C3H4 gases is combusted.During the reaction, 30.8 gram of CO2 gas is produced.Find the mass of C2H6 in the initial mixture.
Answer: Let x = g C 3 H 4 and y = g C 2 H 6 equation 1 is x + y = 10.00 g C 3 H 4...
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If a balloon is filled with He, Ne, and Ar gases at a total pressure of 2.0atm, what is the partial pressure of argon if the partial pressures of helium and neon are both 0.25atm each?
According to Dalton's law of partial pressure:Ptotal = P1 + P2 + P3 ...where Ptotal - total pressure, Pn - partial pressureHere:Ptotal = PHe + PNe + PArAs a result,...
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A gas mixture contains 4.0 g of CO(g), 11.0 g of CO₂(g) and 2.0 g of CH4 (g) in a 50.0 - L vessel. Calculate the partial pressure of each gas in the mixture.
The partial pressure of each gas in a mixture is proportional to its mole fraction.n = m / MM (CO) = 28 g/molM (CO2) = 44 g/molM (CH4) = 16.04...
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What is the partial pressure of sulfur dioxide gas in torr in a sealed vessel that has a total pressure of 520 torr and partial pressures of 0.35 atm for nitrogen?
P_gen=P(〖SO〗_2 )+P(N_2) P(〖SO〗_2 )= P_gen-P(N_2) 1 atm = 760 torr P(N_2 )=(760 torr×0.35 atm)/(1 atm)=266 torr P(〖SO〗_2 )= 520-266=254 (torr) Answer: 254 torr.
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The partial pressure of Ch4(g) is 0.145 atm and that of O2(g) is 0.200 atm in a mixture of the two gases.
What is the mole fraction of each gas in the mixture?
p_i/p_total =x_i=n_i/n_total , where x_i- mole fraction. x_(〖CH〗_4 )= (0.145 atm)/((0.145+0.200) atm)×100%=42.0%; x_(O_2 )=(0.200 atm)/((0.145+0.200) atm)×100%=58.0%. Answer: x_(〖CH〗_4 )=42.0%; x_(O_2 )=58.0%.
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Determine the total pressure of a gas mixture that contains oxygen, nitrogen and helium if the partial pressures of the gases are 20.0kPa, 46.7kPa, and 26.7 kPa.
93.4 kPa
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In a gas mixture composed of N2, Ne, and He, the partial pressure of N2 is 0.50 atm, that of Ne is 1.1 atm, and that of He is 0.80 atm. Calculate the mole fraction of each gas.
Mole fraction of N2- 0.208Mole fraction of Ne - 0.3Mole fraction of He - 0.458
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