P1 = 70 torr , P2 = 30 torrPTotal = P1 + P2 PTotal = 70 torr + 30 torr = 100 torr
1 Answers 1 viewsDalton's law states; The total pressure exerted by a mixture of gases is equal to the sum of the pressures of each of the different gases making up the mixture,...
1 Answers 1 viewsAccording to Dalton's Law of Partial Pressure;Pt= Px +Py+ Pz = (340+264+100)mmHg (since 1torr=1mmHg) = 704mmHg
1 Answers 1 views=341mmHg
1 Answers 1 viewsThe vapor pressure at 28 Co is of 28.3 mm Hg. Based on the Dalton’s law regarding partial pressure of gas mixture the total pressure is defined as follows: P...
1 Answers 1 viewsAs we know, Total pressure is the sum of partial pressure of individual gases.PT = 1.05 -(0.08+0.05+Pair)Pair = [0.92] atm
1 Answers 1 viewsThe partial pressure of each gas in a mixture is proportional to its mole fraction.n = m / MM (CO) = 28 g/molM (CO2) = 44 g/molM (CH4) = 16.04...
1 Answers 1 viewsSolution:Calculate the mole fraction (x) of O2 gas in the mixture:x(O2) = number moles of O2 / total number moles of gasTotal number moles of gas = Moles of...
1 Answers 1 viewsFor this task we use the Dalton’s law which says that total pressure of mixture of gases equals to the sum of partial pressures of individual gases: Ptotal=PA+PB+PC+PD Therefore PD...
1 Answers 1 viewsp_i/p_total =x_i=n_i/n_total , where x_i- mole fraction. x_(〖CH〗_4 )= (0.145 atm)/((0.145+0.200) atm)×100%=42.0%; x_(O_2 )=(0.200 atm)/((0.145+0.200) atm)×100%=58.0%. Answer: x_(〖CH〗_4 )=42.0%; x_(O_2 )=58.0%.
1 Answers 1 views