Login
Get Advice on Live Video Call
Earn $ Cash $ with
consultations on Bissoy App

What volume of 0.1248 M HCl should be added to a 5.0 g sample of CaCO3 for the CaCO3 to react completely. CaCO3 (s) + 2 HCl ==>> CaCL2 + H2O + CO2 (g)

Md Ariful Islam

0 like 0 dislike
1 views
Share with your friends

1 Answers

Md Ariful Islam

Call
As one can see from the reaction equation, two moles of HCl reacts with one mole of calcium carbonate: n(CaCO_3 )=n(HCl)/2. The number of the moles of HCl equals: n(HCl)=c(HCl)·V(HCl)=0.1248 M·V(HCl). Thus, the volume of HCl is: V(HCl)=n(HCl)/(0.1248 M)= 2n(CaCO_3 )/(0.1248 M). The number of the moles of calcium carbonate is its mass divided by its molar mass: n(CaCO_3 )=m(CaCO_3 )/M(CaCO_3 ) = (5.0 g)/(100.09 g/mol)=0.0500 mol. Finally, the volume of HCl solution: V(HCl)= 2n(CaCO_3 )/(0.1248 M)= (2·0.0500 (mol))/(0.1248 M)=0.8006 (L). Answer: 0.8006 (L)
0 like 0 dislike
1 views
Given the reaction: H2SO4 + CaCO3 → CaSO4 + H2O + CO2, and, starting with 2.5 moles of H2SO4, determine the volume occupied by CO2 in the CNTP.

From the equation mole ratio between H2SO4 and CO2 = 1:1Hence 2.5 moles of H2SO4 = 2.5 moles of CO2molar mass of CO2 = 44.01= 44.01 × 2.5= 110.025ml

1 Answers 1 views
Calculate ∆Hrxn for Ca(s) + 1⁄2 O2(g) + Co2 (g) → CaCO3(s) given the following set of reactions: Ca(s) + 1⁄2 O2(g) →CaO(s) ∆H = -635.1 kJ CaCO3(s) →CaO(s) + CO2(g) ∆H = 178.3 kJ

∆Hrxn = ∆H1 + ∆H2= -635+178= -457kJ

1 Answers 1 views
C + 2 H2O  CH4 + CO2 C + H2O  CO + H2 ∆H = +131.3 kJ CO + H2O  CO2 + H2 ∆H = -41.2 kJ CH4 + H2O  3 H2 + CO ∆H = +206.1 kJ

131.3+-41.2-206.1= 116kJ

1 Answers 1 views
Ca(OH)2 + HCl → CaCl2 + H2O How many grams of CaCl2 will be produced from 37 g of Ca(OH)2 and 37 g of HCl?

The balansed reaction is as following:Ca(OH)2 + 2HCl → CaCl2 + 2H2OTo find the mass of the product of the reaction, we need to determine a limiting reactant. For the...

1 Answers 1 views
Ca(CO3)(aq) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g) If 0.0600 g HCl reacts with excess Ca(CO3), what amount (in moles) of CaCl2 will be produced?

Solution:The balanced chemical equation:CaCO3(aq) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)According to the equation: n(HCl) / 2 = n(CaCl2)Moles of CaCl2 = Moles of HCl / 2Moles of HCl...

1 Answers 1 views
What is the percent yield of the following reaction if 3.50 g of CO2 were produced from the reaction of 10.0 g of CaCO3 with excess HBr? CaCO3 (s) +2 HBr (aq) → CaBr2 (aq) + H2O (l) + CO2 (g)

79.5%

1 Answers 1 views
2LiOH(s) + CO2(g) --> Li2CO3(s) + H2O(l) There is 3.0 L of CO2 gas at a pressure of 1.5 atm and a temperature of 300 K. What mass of LiOH would be used to react with this amount of CO2?

pV= nRT.n= pV/RT = 1.5 x 3 / 0.082 x 300 = 0.182926829 moles of CO2m= 2 x 0.182926829 x 24 = 8.7804878 g of LiOH

1 Answers 1 views
How many liters of O2 (g) are needed to react completely with 56.0 L of CH4 (g) at STP to produce CO2 (g) and H2O (g)? Given: CH4 (g) + 2O2 (g) → CO2 (g) + H2O (g)

According to the equation 1L of CH4 reacts with 2L of O2. Volume of O2 = V(CH4) *2 = 56*2 = 112 L

1 Answers 1 views
Please pick the correct expression for the following equilibrium expression: CO (g) + H₂O (g) <--> CO₂ (g)+ H₂ (g) * [CO₂] [H₂] / [CO] [H₂O] [H₂] /[CO] [CO] [H₂O] / [CO₂] [H₂]

[CO₂] [H₂] / [CO] [H₂O] 

1 Answers 1 views
Magnesium reacts with HCl to produce MgCl2 and hydrogen gas. How many liters of a 1.85 M HCl solution completely react with 4.00 grams of magnesium? Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)

1 mole of Mg reacts with 2 moles of HCl24g of Mg reacts with 2 moles of HCl1g of Mg will react with 2/24 moles of HCl4g of Mg will...

1 Answers 1 views

Log in to ask questions, provide answers, or leave comments.


Login

Install the Bissoy app to consult with a doctor.


Download