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The balansed reaction is as following:
Ca(OH)2 + 2HCl → CaCl2 + 2H2O
To find the mass of the product of the reaction, we need to determine a limiting reactant. For the purpose, we need to calculate the number of moles of Ca(OH)2 and HCl used in the reaction.
The number of moles equals:
n = m / Mr
where n - number of moles, m - mass, Mr - molecular weight.
From here:
n(Ca(OH)2) = 37 g / 74 g/mol = 0.5 mol
n(HCl) = 37 g / (2 × 36.5 g/mol) = 0.5 mol
The results show that there is no limiting reactant as the number of moles of both reactants are equal. As a result, the number of moles of CaCl2 produced in the reaction also equals 0.5 mol.
As n = m / Mr:
m(CaCl2) = n(CaCl2) × Mr(CaCl2) = 0.5 mol × 111 g/mol = 55.5 g
Answer: 55.5 g
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