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How many mL of 0.548 M HCl are needed to dissolve 5.89 g of CaCO <sub>3 </sub>? 2HCl (aq) + CaCO <sub>3 </sub>(s) CaCl <sub>2 </sub>(aq) + H<sub>2</sub>O(l) + CO<sub>2</sub>(g)
Molar mass of CaCO3= 100.0869 g/mol5.89/100.0869= 0.059molMole ratio HCl: CaCO3= 2:10.059×2= 0.108molMolar mass of HCl = 18.0150.108×18.015= 1.95g0.548×18.015=9.87g9.87/1.95= 5.063g
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How many mL of 0.548 M HCl are needed to dissolve 5.89 g of CaCO <sub>3 </sub>? 2HCl (aq) + CaCO <sub>3 </sub>(s) CaCl <sub>2 </sub>(aq) + H<sub>2</sub>O(l) + CO<sub>2</sub>(g) _____________mL
Molar mass of CaCO3= 100.0869 g/mol5.89/100.0869= 0.0588molMolar mass of HCl= 36.458 g/mol0.0588×36.458×2= 4.29ml
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How many moles of CO<sub>2</sub> will be produced when you burn 12.5 moles of C<sub>2</sub>H<sub>4</sub>? ( C<sub>2</sub>H<sub>4</sub> + 3 O<sub>2</sub> ---> 2 CO<sub>2</sub> + 2 H<sub>2</sub>O )
Mole ratio C2H4:CO2=1:2= 12.5×2=25moles of CO2
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Can you please help me balance this equation?Na[sub]3[/sub]PO[sub]4[/sub] + Ba(NO[sub]3[/sub])[sub]2[/sub] = Ba[sub]3[/sub](PO[sub]4[/sub])[sub]2[/sub] + NaNO[sub]3[/sub]
The correct balanced equation is: Na3PO4 + Ba(NO3)2 = BaPO4 + Na3(NO3)2
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2HCl + Ba(OH) <sub>2</sub> --> BaCl <sub>2</sub> + 2H <sub>2</sub>O If you have 50.0 grams of Ba(OH) <sub>2</sub>, how many grams of BaCl <sub>2</sub> can you make?
2HCL = 2molBa(OH)2 = 1molBaCl2 = 1 mol2H2O = 2molMolar Mass BaCL2 = 208.23g/molMolar Mass of Ba(OH)2 = 171.34g/molUsing the ratio(208.3g/mol Bacl2/ 171.34Ba(OH)2) ×50 = 60.78557= 60.79g Bacl2
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2HCl + Ba(OH) <sub>2</sub> --> BaCl <sub>2</sub> + 2H <sub>2</sub>O If you have 80.0 grams of HCl and 50.0 grams of Ba(OH) <sub>2</sub>, how many grams of BaCl <sub>2</sub> can you make?
2HCL = 2molBa(OH)2 = 1molBaCl2 = 1 mol2H2O = 2molMolar Mass BaCL2 = 208.23g/molMolar Mass of Ba(OH)2 = 171.34g/molUsing the ratio(208.3g/mol Bacl2/ 171.34Ba(OH)2) ×50 = 60.78557= 60.79 Bacl2Molar Mass of...
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Using the following chemical equation how many grams of water are produced by reacting 59.33 g of calcium hydroxide? 2HCl + Ca(OH)<sub>2</sub> -> 2H<sub>2</sub>O + CaCl<sub>2</sub>
Solution:The balanced chemical equation:Ca(OH)2 + 2HCl → CaCl2 + 2H2OAccording to the equation above: n(Ca(OH)2) = n(H2O)/2Moles of Ca(OH)2 = Mass of Ca(OH)2 / Molar mass of Ca(OH)2The molar mass of Ca(OH)2...
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Using the following chemical equation how many grams of calcium chloride are produced when 18.84 g of water are produced? 2HCl + Ca(OH)<sub>2</sub> -> 2H<sub>2</sub>O + CaCl<sub>2</sub>
Solution:The balanced chemical equation:Ca(OH)2 + 2HCl → CaCl2 + 2H2OAccording to the equation above: n(CaCl2) = n(H2O)/2Moles of H2O = Mass of H2O / Molar mass of H2OThe molar mass of H2O is 18.0153 g...
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Using the following chemical equation how many grams of water can be produced by reacting 15.33 g of hydrochloric acid (HCl)? 2HCl + Ca(OH)<sub>2</sub> -> 2H<sub>2</sub>O + CaCl<sub>2</sub>
According to the equation, equal numbers of moles of HCl and water must react and be produced, respectively. From here:m(water) = [m(HCl) × 2 × Mr(water)] / [2 × Mr(HCl)]...
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(NH<sub>4</sub>)<sub>2</sub>CO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub> → (NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O net ionic equation
2 NH4 + + CO3 -2+ 2H + +SO4 2-= 2 NH4 + +SO4 2-+ CO2+H2O2NH4++CO3−2+2H++SO42−=2NH4++SO42−+CO2+H2O
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