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The standard enthalpy of the reaction: CO(NH2)24) + H20) -› CO2(g) + 2 NHa(a) is -133.42 kJ/mol. Calculate the standard enthalpy of formation of urea, CO(NH2)2(6).
Standard enthalpy of formation=-362kJ/mol
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the standard enthalpy of formation of urea, CO(NH2)2(6). The standard enthalpy of the reaction: CO(NH2)2() + H2Om) -› COz) + 2 NHare) is -133.42 kJ/mol. Calculate
Standard enthalpy of formation=-362kJ/mol
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Sodium chloride reacts with sulfuric acid. If 30.0 g of sodium chloride are available, and 14.6 g of the chloride product form, what is the percentage yield?
Explanation:First, we ensure that the equation is balanced. Then, we convert the given grams to moles of reactant. We use that to determine the moles of the product from the...
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Explain the following terms:
i) Integral enthalpy of solution
ii) Differential enthalpy of solution
iii) Enthalpy of dilution
I. Integral Enthalpy Of Solution is the heat absorbed or released when a solute is dissolved in a definite amount of solvent. The heat of solution depends on the nature...
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the standard enthalpy of combustion of ethane, carbon, and hydrogen are -1559.7 kJ/mol, -393kJ/mol and -286kJ/mol respectively.
Use Hess'ss law to find the enthalpy of formation of ethane
ΔHform(C2H6)=ΔHcomb(C2H6)-(2ΔHcomb(C)+3ΔHcomb(H2))=-1559.7-(2(-393)+3(-286))=84,3 kJ/mol
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Calculate the number of grams of solution necessary to provide the following:
a. 68.5 g of sodium chloride from a 12.0% sodium chloride solution
12% means 12 grams NaCl / 100 g solution. Therefore:68.5 g NaCl X (100 g Solution / 12 g NaCl) = 571 grams of solution is needed.
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If 86.33 grams of sodium reacts with an excess of chlorine, what amount of Salt (sodium chloride) will be produced? Sodium + chlorine ® sodium chloride Na + Cl2 ® NaCl
Solution:Sodium + chlorine → sodium chloride The balanced chemical equation:2Na + Cl2 → 2NaClAccording to the equation above: n(Na) = n(NaCl)Moles of Na = Mass of Na / Molar mass of NaThe molar...
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table salt, or sodium chloride is composed of 28.3% sodium and 71.7% chlorine. Calculate the mass of chlorine in 7.0 g of sodium chloride
Answer: 7.0 g NaCl x 0.717 %Cl/NaCl = 5.019 g Cl
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Which of the above equilibria is forced to shift furthest to the left? Explain.
- Lead nitrate and Sodium chloride
- Lead chloride and Sodium chromate
-Lead chromate and Sodium sulphide
Answer: Combination which makes less soluble product shift towards left side of the equation.Pb(NO3)2 + 2NaCl = PbCl2 + 2NaNO3PbCl2 + Na2CrO4 = PbCrO4 + 2NaClPbCrO4 + Na2S = PbS...
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Your first task is to prepare 100mL of a 1.0 mol/L solution of sodium chloride using solid sodium chloride. Calculate the mass of solid sodium chloride needed.
m(NaCl) = M(NaCl) * Vsolution * CM = 58.5 * 0.100 * 1 = 5.85 (g)Answer: 5.85 g of solid sodium chloride needed.
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