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Rock salt is a mixture of common salt(sodium chloride) and sand. Describe how you can obtain a sample of dry pure sodium chloride from a sample of rock salt.
You can remove most of these contaminants using two simple purification techniques: filtration and evaporation.
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1.15g of sodium reacts with an excess of chlorine, forming 1.872g of sodium chloride. What is the percentage yield of sodium chloride
the percentage yield of sodium chloride is 63,78%
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Can salt be lost during evaporation because after evaporating H20 from NaCl i was left with 0.1g of salt but using the equation m=n×M there should of been 0.1255g of salt. How was the salt lost?
Sodium chloride is not decomposed when heated in water and you could not lose it that way. It is lost due to experimental error (maybe spillage of the solution)
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Sodium and chlorine combine to form sodium chloride. How many grams of sodium chloride are produced if 8.3 moles of chlorine react?
n(Cl2) = 8.3 molesSolution:Sodium + chlorine = sodium chloride.The equation of a chemical reaction:2Na + Cl2 = 2NaClAccording to the chemical equation: n(Na)/2 = n(Cl2) = n(NaCl)/2.Therefore,n(NaCl) = 2*n(Cl2) =...
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If 86.33 grams of sodium reacts with an excess of chlorine, what amount of Salt (sodium chloride) will be produced? Sodium + chlorine ® sodium chloride Na + Cl2 ® NaCl
Solution:Sodium + chlorine → sodium chloride The balanced chemical equation:2Na + Cl2 → 2NaClAccording to the equation above: n(Na) = n(NaCl)Moles of Na = Mass of Na / Molar mass of NaThe molar...
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sodium chloride is 39.34% sodium. what mass of sodium chloride will contain 2.00 g of cholrine
Solution: If sodium chloride is 39.34% sodium, then chlorine in sodium chloride: 100 – 39.34 = 60.66% If in 60.66% - 2 g in 100% - x, Then x=100x2/60.66=3.297 g...
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A compound is composed of 23.0 g sodium and 35.0 g chlorine is available for reaction, what mass of sodium is needed to complete the salt reaction?
Explanation:The reaction that takes place is:Na + Cl -> NaClthe ratio of this reaction is 1 : 1 : 1Na =22.9898 g/mole g/moleCl = 35.453 g/moleNaCl = 58.44 g/moleFirst you...
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A solution consisting of acid HA and salt KA If the pH value before adding salt is 3 and after adding salt 5 Calculate the concentration of the added acid
Your question is not clear and detailed. Well, I presume you meant a substance (salt) was added to an acid with the PH of 3. After adding it the PH...
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Your first task is to prepare 100mL of a 1.0 mol/L solution of sodium chloride using solid sodium chloride. Calculate the mass of solid sodium chloride needed.
m(NaCl) = M(NaCl) * Vsolution * CM = 58.5 * 0.100 * 1 = 5.85 (g)Answer: 5.85 g of solid sodium chloride needed.
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