Which of the above equilibria is forced to shift furthest to the left? Explain. - Lead nitrate and Sodium chloride - Lead chloride and Sodium chromate -Lead chromate and Sodium sulphide

Md Ariful Islam

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Answer: Combination which makes less soluble product shift towards left side of the equation.

Pb(NO3)2 + 2NaCl = PbCl2 + 2NaNO3

PbCl2 + Na2CrO4 = PbCrO4 + 2NaCl

PbCrO4 + Na2S = PbS + 2NaCrO4

PbS and PbCrO4 is less soluble in water, so equilibrium will shift towards left side in this two cases.

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Pb(NO3)2 (aq) + 2 NaI (aq) → PbI2 (s) + 2 NaNO3 (aq)2Na(+) +2I(-) + Pb(2+) + 2NO3(-) = 2Na(+) +PbI2(s) + 2NO3(-)2I(-) + Pb(2+) = PbI2 (s)Lead iodide appears as a yellow crystalline solid. Insoluble in water.

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Molar mass of Pb= 207.2g500/207.2= 2.413Mole ratio Pb:O2= 2:3Molar mass of O2= 31.998= 31.998×2.413×3/2= 115.823g

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Solution Write the reaction equation: Pb(NO3)2 + 2NaCl  PbCl2 + 2NaNO3 So 1 mole of Pb(NO3)2 reacts with 2 moles of NaCl. Find the amount of Pb(NO3)2 (331 g/mole):...

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Answer:2HNO3 = 2HNO2 + O2m= 85 x 0.1235 / 69= 0.1521W%= 0.1521 / 0.4230 = 36%

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2Ag+ (aq) + CrO42- (aq) ↔ Ag2CrO4 (s)mol Ag+ (aq) = (0.120 L)(0.045 mol/L) = 0.0054 mol Ag+[Ag+] = 0.0054 mol/(0.120 L + 0.180 L) = 0.0054 mol / 0.300...

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When lead nitrate reacts with sodium iodide, sodium nitrate and lead iodide are formed.

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An improvement in technology shifts the supply curve outward (to the right) because the cost to produce the good decreases, so they can make more products at a lower cost...

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