1 mole of argon = 6.02 × 1023= 1.475 × 1024/6.02 × 1023= 2.4502 moles of argon
1 Answers 1 viewsYou can use the following law for solving this question: PfVf = P1V1 + P2V2 + P3V3 hellip; etc Pf is final pressure of the mixture Vf is Final volume...
1 Answers 1 viewsThe partial pressure of individual gas in the gas mixture can be expressed the following way: Pi = Ptotal *xi, Where Pi – is the partial pressure of individual gas...
1 Answers 1 viewsV= 2x10-3m3 = 2dm3m= 0.036Kg = 36gT= 300KR= 0.0821L.atm/k.molnumber of moles, n= mass/Molar mass = 36/39.9= 0.9molPV= nRTP= nRT/Vp= 0.9x0.0821x300/2P= 11.08atm
1 Answers 1 views79.9= 3.626? = 179.9× 1/3.626= 22.0422.04/211.02Nitrogen gas
1 Answers 1 views69.22lb/ft3=1.1088 g/mL.Therefore the unknown liquid is ethylene glycol.
1 Answers 1 viewsVapor pressure is a property of a liquid based on the strength of its inter-molecular forces. A liquid with weak inter-molecular forces evaporates more easily and has a high vapor...
1 Answers 1 viewsOne mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).Proportion:1 mole – 22400 mln moles –...
1 Answers 1 viewsQUESTION # 136434The reduction of titanium (IV) chloride to titanium cannot be carried out in air. The air has to be replaced with argon gas. Explain why air needs to...
1 Answers 1 viewsVolume = Mass / Density = 143g / 1.62g/mL = 88.27mL
1 Answers 1 views