112 mL of NO2(g) at STP was liquefied, the density of the liquid being 1.15 g mL Calculate the volume of liquid and the number of molecules in the liquid NO2

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Md Ariful Islam · Answer 1 · Apr 23, 2024 22:52:18

One mole of an ideal gas will occupy a volume of 22.4 liters at STP (Standard Temperature and Pressure, 0°C and one atmosphere pressure).

Proportion:

1 mole – 22400 ml

n moles – 112 ml

n = 0.005 moles of NO₂

m=n×M

M(NO₂) = 46 g/mol

m(NO₂) = 0.005×46=0.23 g

ρ(NO₂) =1.15 g/ml

V = m/ρ

V = 0.23/1.15 = 0.2 ml

One mole of NO₂ molecules contains 6.02×10²³ NO₂ molecules

Number of molecules = n×6.02×10²³ = 0.005×6.02×10²³ = 3.01×10²¹molecules

Answer: 0.2 ml and 3.01×10²¹molecules

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