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If a child drank 15.0 mL of ethylene glycol (antifreeze, d = 1.11 g/mL), how many grams were consumed?
Mass =Density ×Volume Mass =(15.0mL ×1.11g/mL) Mass =16.65g
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An aqueous solution of ethylene glycol is 40.0% C2H6O2 by mass and has a density of 1.05 g/mL. Determine the molality (m) of C2H6O2 in this solution. (past years 2020)
Molarity=28.2M
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in which chemical Dipropylene glycol can be added which will make Dipropylene glycol thin without changing its property. and it should be transparent(Dipropylene glycol)
Dipropylene glycol is a colorless, practically odorless liquid with a medium viscosity. It is completely soluble in water and is hygroscopic (attracts water from the atmosphere). The Dow Chemical Company...
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the alcohol that gives turbid mixture when mixed with lucas reagent after warming at 60c after 5 minutes in: a) 2-methylpropanol b) 2,2-dimethylpropanol c) Propanol D) ethylene glycol
b) 2,2-dimethylpropanol
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Find the mole fraction of 18.93% m/m of ethylene glycol in 112 g of aqueous ethylene glycol solution.
As given in the question, a solution of ethylene glycol and water contains 20% of ethylene glycol by mass.That is, in 112g of solution - 21.202g of ethylene glycol.Molar mass...
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What is the mass, in grams, of 30.0mL of the liquid propylene glycol, with a density of 1.036g/mL at 25 degrees Celsius?
m= pV = 1.036 * 30 = 30.08 g
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Into how much water should you dissolve 80.0 g ethylene glycol in order to obtain a solution with a concentration of 4.9 m?
M((CH2OH)2)=62 g/mol n((CH2OH)2)=m/M=80/62=1.29 mol c=n/V 4.9 M = 1.29 mol / x L ---> x=1.29/4.9=0.26 L V(H2O)=0.26 L = 260 ml
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Calculate the molality of a solution containing 14.5 g of ethylene glycol (C2H6O2) dissolved in 150 g of water.
Amount of ethylene glycol: 14.5 / 62.07 = 0.2336 mol Molality: 0.2336 / 0.150 = 1.557 mol/kg
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What volume of ethylene glycol, an anti-freezing agent, C2H6O2 (p=1.12g/ml) must be added to 20.0ml of water in a car radiator to produce a solution that freezes at -10.0C?
Answer: 5.95 ml delta Tf = Kf × m where delta Tf = depression in freezing point since pure water freezes at 0 degree C but this solution is freezing...
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An unknown gas is found to be 2.25 times faster than Diphosphorus Pentoxide. What is the molar mass of the unknown gas?
Use four significant figures AND do NOT include units
R1/R2=√M2/M1R1/R2=2.252.25=√M2/M1M1=M2/5.0625M1= 142/5.0625 = 28.
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