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Number of moles of HCI (MM=36.46 g/mol)needed to completely react with Ca(OH)₂.The molar mass of Ca(OH)₂ is 74.10 g/mol.
Ca(OH)2+2HCl=CaCl2+2H2Ov(Ca(OH)2)=v/2(HCl)=0.5molv(HCl)=1mol
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Number of moles of HCI (MM= 36.46 g/mol) needed to completely react with Ca(OH2). The molar mass of Ca(OH2) is 74.10 g/mol
2 HCl (aq) + Ca(OH) 2 (s) → CaCl 2 (aq) + 2 H 2O (l)=2 moles
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If 2.00 moles of H2 and 1.55 moles of O2 react how many moles of H2O can be produced in the reaction below? 2H2+O2+2H2O
In this reaction O2 is the excess reactant and H2 is the limiting reactant, because:n(H2)/2 < n(O2)/1 ; 1<1.55;1 and 2 - stoichiometric coefficients of O2 and H2 respectively;That's why...
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<ol><li>10 mol of Zn react with 10 mol of HCl. Calculate the number of moles of H2 produced.</li></ol> (a) 5 mol (b) 10 mol (c) 20 mol (d) 2.5 mo
ANSWER SHOUD BE "a".EXPLANATION ......Zn reacts with HCl and form ZnCl2 and H2 .Balance Reaction is Zn + 2HCl ----- ZnCl2 + H2 .When 10 mol of Zn react with...
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1. Considering the following reaction: 3Si + 2n2 →Si3N4 2. When 26.8 moles of Si react with 21.845 moles of N2, how many moles of Si3N4 are formed? 3. What is the limiting reactant?
Mole ratio of Si:Si3N4= 3:1= 26.8/3= 8.933Mole ratio N2: Si3N4=2:1= 21.845/2= 10.923= 10.923+8.933= 19.856moles
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Nitric acid is formed by the reaction of nitrogen dioxide with water. How many moles of water are needed to react with 8.4 mol of nitrogen dioxide?
3NO2 (g) + H2O (l)------> NO (g) + 2HNO3 (aq)
Accordinng to the equation 3NO2(g) + H2O(l)------gt; NO(g) + 2HNO3(aq) we can find the amount of substance of water: n(NO2) : n(H2O) = 1:3; n(H2O) = n(NO2)*1/3 If the amount...
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In reaction
CH.(9)+30 (9) ► 20092110
How many (a)moles of O are consumed and (b)moles of H,O are formed when 4.16 102 mol of CH, react?
From the context of this question: CH4+2O2 = CO2+2H2On(O2)= n (H2O) =2 x n (CH4) = 2 x 4.16102 = 8.32204 moles
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Calculate number of moles in
A)7.85gm Fe (molar mass =56 gm/mol)
B)4.68 mg of Si (molar mass =28.1gm/mol)
n=m/M A. n = 7.85g / 56g/mol = 0.14 mol B. n = 0.00468g / 28.1 g/mol = 0.00017
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how many moles of hydrogen are needed to completely react with 1.23 moles of nitrogen?
According to the reaction equation:N2+3H2=2NH3n(H2) = n(N2) *3 = 1.23 mol * 3 = 3.69 molAnswer: 3.69 mol
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