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4NH3+302-> 2N2+6H2O determine the amount of grams of N2 (fw= 28 g/mol) is produced if 4.03 miles of NH3 react
Quality of moles N2 = 4.03/4*2=2.015. 2.015*28 g/mol= 56.42 g.
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If 145g N2H4 and 175g of N2O4 are allowed to react N2H4 (1)+N2O4=N2(g)+H2O(1) datermine the limiting reactant,mass(in grams)of excess reactant and mass(in grams) of water
The limiting reactant is N2O4. Mass of excess reactant =35.7gMass(in grams) of water=71.4g
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Nitrogen gas and hydrogen gas are combined in a reaction to produce ammonia. If 6.0 moles of N2 and 6.0 moles of H2 are present in the mixture, which is the limiting reactant?
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The hydrogen gas will act as a limiting reagent, i.e. it will limit the amount of nitrogen that takes part in the reaction.
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How many grams of ammonia can be made by reacting 100 g of N2 with 20 g of ? What is the limiting reactant? How much of the excess reactant will be left over? N2(g) + 3H2(g) → 2NH3(g)
Molar mass of N2 = 28.0134100/28.0134 = 3.57molesMolar ratio of N2:NH3 = 1:23.57 × 2 = 7.14moles of NH3Molar mass of H2 = 2.01620/2.016 = 9.92molesMole ratio of H2:NH3 =...
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MnO2 + HCl = MnCl2 + Cl2 + H2O If 1.92 mol of MnO2 and 96.4g of HCl react, determine the limiting reagent. Also determine the mass of Cl2 and the mass of unused reactant after the reaction.
=23g of Chlorine will be produced.
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Consider the following balanced equation: 3NH4NO3 + Na3PO4 → (NH4)3PO4 + 3NaNO3 30 g NH4NO3 and 50 g Na3PO4 are allowed to react. -Which reactant is the limiting reactant?
3NH4NO3 + Na3PO4 → (NH4)3PO4 + 3NaNO3UMole ratio for NH4NO3 : Na3PO4Is 3 : 1 Moles of NH4NO3= mass/Molecular massMolecular mass= 14+ 4 +14 +16×3= 80Moles = 30÷80 = 0.375Moles...
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In a chemical reaction, your limiting reactant was used up. You have a large quantity of excess reactant remaining. Will the reaction procees? Why or why not?
No, we don't have all reactants required for the reaction, so it wouldn't proceed.
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Considering the limiting reactant, what is the volume of NO gas produced from 60.0 L of ammonia gas and 50.0 L of oxygen gas? (Assume constant conditions.)
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)
Volume of reactants is proportional to coefficient in equation. So for this reaction we need correlation of volumes NH3 : O2 like 4:5 and we have 60:50,so NH3 is in...
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H2 can be generated from 15.38g of AI and 0.037 moles of NaOH when they react in excess water. What is the limiting reactant
Solution:The balanced chemical equation:2Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2According to the equation above: n(Al) = n(NaOH)Moles of NaOH = 0.037 mol15.38 g Al × (1 mol Al /...
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When 0.85mol of zinc nitrate react with 0.254mol of sodium phosphate insoluble zinc phosphate forms. Which is the limiting reactant and which is the reactant in excess?
Solution:zinc nitrate = Zn(NO3)2sodium phosphate = Na3PO4zinc phosphate = Zn3(PO4)2Balanced chemical equation:3Zn(NO3)2(aq) + 2Na3PO4(aq) → Zn3(PO4)2(s) + 6NaNO3(aq)According to stoichiometry:3 mol of Zn(NO3)2 reacts with 2 mol of Na3PO4Thus 0.85 mol...
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