NH3 reacts with water to form NH4OHNH4OH is a weak base.NH4OH(aq) = NH4+(aq) + OH-(aq)Kb = [NH4+]×[OH-]/[NH4OH]or,Kb= [OH-]^2/[NH4OH]or,1.8×10^-5 = [OH-]^2/2.4×10-4or,[OH-]^2= 4.32×10-9or,[OH-] = 6.57×10-5pOH = -log[OH-]= -log(6.57×10-5)= 4.18Therefore, pH= 14–4.18= 9.82...