How many chromium atoms in a $5.67*g$ mass of chromium metal?

Md Ariful Islam

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Md Ariful Islam

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The molar mass of elemental chromium is $52.00*g*mol^-1$. What does this mean? It means that if there are $52.00*g$ of chromium metal, there are $"Avogadro's number"$ of chromium atoms, i.e. $N_A$ chromium atoms, or $6.022xx10^23$ individual atoms.

Here, I have used $N_A$ as I would a dozen, or a score, or a gross, or any other collective number.

So the number of atoms?

$(5.67*g)/(52.00*g*mol^-1)xx6.022xx10^23*mol^-1$ $=$

$"How many chromium atoms?"$

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