We solve for
Clearly we get an answer with units of volume as required. Do you agree? And remember
Use the : $P_1 V_1 = P_2 V_2$ . substituting and making the units consistent: $(200xx10^3)(2500)=(500xx10^3)(V_2)$. solve for $V_2$ .
1 Answers 1 views$V_2$ $=$ $(P_1V_1T_2)/(P_2T_1)$ $(12*atmxx23*Lxx300K)/(14*atmxx200*K)$ $=$ $??L$ The volume has increased reasonably in that the temperature has increased substantially, yet the pressure has only increased marginally.
1 Answers 1 viewsRaising the temperature will increase the volume: $V_T=(300K)/(200K)xx24.0L=36.0L$ Increasing the pressure will decrease the volume: $V_(T,p)=(10.0atm)/(14.0atm)xx36.0L~~25.7L$ It doesn't matter if you first do the one and then the other, or...
1 Answers 1 viewsAnd so.................. $V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)$ $=(2.31*atmxx17.5*Lxx350*K)/(299*Kxx1.75*atm)<=30*L.$
1 Answers 1 viewsAnd thus $760*mm*Hg-=1*atm$ The combined gas equation tells us that $(P_1V_1)/T_1=(P_2V_2)/T_2$ given a constant molar quantity of gas. So we solve for $V_2$, where $V_2$ is conceived to be the...
1 Answers 1 viewsFirst, write the balanced chemical equation for the equilibrium and set up an ICE table. $color(white)(XXXXXX)"N"_2 color(white)(X)+color(white)(X)"3H"_2 color(white)(l)⇌ color(white)(l)"2NH"_3$ $"I/atm": color(white)(Xll)1.05 color(white)(XXXl)2.02 color(white)(XXXll)0$ $"C/atm": color(white)(X)-x color(white)(XXX)-3x color(white)(XX)+2x$ $"E/atm": color(white)(l)1.05- x...
1 Answers 1 viewsBoyle's law states that for a fixed mass of gas at constant temperature, the absolute pressure and the volume of a gas are inversely proportional. $p1*v1 =p2*v2$ So, $p1*v1 =p2*v2$...
1 Answers 1 views$(P_1V_1)/T_1=(P_2V_2)/T_2$ You need to convert degC to Kelvin by adding 273: $:.(200xx25)/298=(250xxV_2)/273$ $:.V_2=(200xx25xx273)/(298xx250)$ $:.V_2=18.32"L"$
1 Answers 1 viewsEven without doing any calculations, you should be able to look at the information given and predict that the volume of the gas will increase after temperature is increased and...
1 Answers 1 viewsThis is an example of a problem. $color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2|)$ We can rearrange this formula to get $V_2 = V_1 × P_1/P_2 × T_2/T_1$...
1 Answers 1 views