How do you use the molar volume gas at STP to determine the volume (in L) of a occupied by 33.6 g of neon at STP?

Md Ariful Islam

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Md Ariful Islam

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So neon occupies 33.6 g

First we find the number of moles of Ne= $(mass)/"molar mass"$
No. of moles= $(33.6)/"20"$
No. of moles= 1.68 mol

Then, we can find volume of the gas using:
No. of moles= $(volume)/"molar volume"$

where molar volume of the gas at stp= 22.4 $Lmol^-1$

Make volume the subject of the formula

Volume= no. of moles x molar volume
Volume= 1.68 x 22.4

Volume of Ne= 37.6 L

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