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A student collects a sample of gas and finds that 1.01 g of the gas will fill a container with a volume of 0.225 L at STP. What is the molar mass of the gas?

Md Ariful Islam

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Md Ariful Islam

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At STP, we know that the is $22.42L/(mol)$, therefore, now we can calculate the number of mole of the gas from its volume $V=0.225L$ at STP.

$=>n=0.225cancel(L)xx(1mol)/(22.42cancel(L))=0.01 mol$

From the number of mole and the mass of the sample ($m=1.01g$) we can find the molar mass of the gas:

$n=m/(MM)=>MM=m/n=(1.01g)/(0.01mol)=101g/(mol)$

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