$1 "mol" " Mg"("ClO"_4)_2$ contains :- $color(red)(1 "mol Mg atoms")$ $color(blue)(2 "mol Cl atoms"$ $color(green)(8 "mol O atoms"$ To find no. of moles of each element,...
1 Answers 1 viewsOld $"Dalton's Law of Partial Pressures"$ states that in a gaseous mixture, the exerted by a component gas is the same as it would have exerted if it alone occupied...
1 Answers 1 viewsWe apply $P_1V_1=P_2V_2$ The initial volume is $V-1=21L$ The initial pressure is $P_1=1.3 atm$ The final pressure is $P_2=3.9atm$ The final volume is $V_2=P_1/P_2*V_1=1.3/3.9*21$ $=7 L$
1 Answers 1 viewsWe can use the to calculate the partial pressures. $color(blue)(bar(ul(|color(white)(a/a)pV = nRTcolor(white)(a/a)|)))" "$ or $p = (nRT)/V$ The number of moles $n$...
1 Answers 1 viewsDalton's law of partial pressures states that in a gaseous mixture, the pressure exerted by a component is the same as it would exert if it alone occupied the container....
1 Answers 1 viewsThe total pressure is the sum of the pressures of the three gases in the flask. $"pressure"_"total" ="11.4 atm + 5.6 atm + 8.7 atm" = "25.7 atm"$
1 Answers 1 views$P_"container"=P_"gas B"+P_"SVP"$. Here $P_"SVP"$ is the so-called $"saturated vapour pressure (of water)"$. $P_"SVP"$ is usually tabulated, and (typically) quoted in units of $mm*Hg$; it varies according to temperature. Are you...
1 Answers 1 views$"Mole fraction of a gas"=("Number of moles of gas")/("Total moles of gas")$ For $O_2$: $"Mole fraction of"$ $O_2$ $= 0.250/(0.250+0.134+0.297)=0.250/0.681~~0.367$ $"Partial pressure of a gas" = "Mole fraction"...
1 Answers 1 viewsThe idea here is that the of each gas will be proportional to the mole fraction each gas has in the mixture $->$ think Dalton's Law of Partial Pressures....
1 Answers 1 viewsFirst convert the temperature to kelvin: $17+273=290$ $K$. Standard temperature is $273$ $K$. Now $100$ $kPa$ is already standard pressure, so the pressure is constant. We should work in...
1 Answers 1 views