Call

And thus for this example $%"Yield"$ $=$ $(7.2*g)/(10*g)xx100%$

And we don't even need a calculator.........

Most of the time, we write a stoichiometric equation, that shows the molar equivalence between reactant and product, so that we can work out the etc.......

$H_2SO_4(aq) + 2NaOH(aq) rarr Na_2SO_4(aq) + 2H_2O$.

At any rate, you have not really quoted starting conditions here.