As with all these problems, we calculate the molar quantities of each substituent, and normalize them according to the masses of the atomic constituents: $"Moles of metal"$ $=$ $(1.19*g)/(52.00*g*mol^-1)=0.0229*mol$ $"Moles...
The idea here is that you need to use the mass of copper and the mass of the copper sulfide to determine how much sulfur the produced compound contains, then...
The first step for any chemical reaction is to write out the chemical equation to determine the molar ratios of the reactants and products. Then we will use the molecular...
$"Moles of iron"$ $=$ $(2.561*g)/(55.85*g*mol^-1)$ $=$ $0.0459*mol$ $"Moles of sulfur"$ $=$ $(2.206*g)/(32.06*g*mol^-1)$ $=$ $0.0688*mol$ If we divide thru by the lower molar quantity, we get, $FeS_(1.5)$. However, by definition, the...
So let us take the weighted average of your : $(50xx0.0434 + 52xx0.8379+53xx0.095+54xx0.0237)g*mol^-1$ $=$ $??$ The final answer should be close to $52$ $g*mol^-1$ because $""^52Cr$ is the most abundant...
The molar mass of elemental chromium is $52.00*g*mol^-1$. What does this mean? It means that if there are $52.00*g$ of chromium metal, there are $"Avogadro's number"$ of chromium atoms, i.e....
To find the mass of the chronium-51 sample that remains after $84$ days, we can use the half-life formula. Recall the half-life formula: $color(blue)(|bar(ul(color(white)(a/a)A=A_0(1/2)^(t/h)color(white)(a/a)|)))$ where: $A=$final amount $A_0=$initial amount...
Sodium chloride is composed of $Na^+$ ions and $Cl^-$ ions. Now of course salt is neutral; and to ensure this sodium ion and chloride ions combine 1:1. On the other...
$Ca(HS)_2$, $"calcium hydrogen sulfide........."$ Calcium forms a $Ca^(2+)$ ion, and thus requires 2 negative charges to form a neutral salt. The salts of $H_2S$ could be sulfides, $S^(2-)$, or hydrogen...
Both are actually correct. For consistency, IUPAC has defined the "parent molecule" as "sulfane" with acceptable "official" names of both "hydrogen sulfide" and "dihydrogen sulfide" (actually preferred, both are "Compositional...
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