Aluminum will react with sulfuric acid in the following reaction: $2Al(s) + 3H_2SO_4(l) -> Al_2(SO_4)_3(aq) + 3H_2(g)$. How many moles of $H_2SO_4$ will react with 18 mol Al? How many moles of each product will be produced?

Md Ariful Islam

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Md Ariful Islam

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With reference to the given balanced equation for the , the needed number of moles for each remaining compound involved in the reaction using the mass of $Al$ as basis for the molar conversions can be computed as;

$etaH_2SO_4:$
$=18cancel(molAl)xx(3molH_2SO_4)/(2cancel(molAl))$
$=27molH_2SO_4$

$etaAl_2(SO_4)_3:$
$=18cancel(molAl)xx(1molAl_2(SO_4)_3)/(2cancel(molAl))$
$=9molAl_2(SO_4)_3$

$etaH_2:$
$=18cancel(molAl)xx(3molH_2)/(2cancel(molAl))$
$=27molH_2$

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