How many moles of aluminum, sulfur, and oxygen atoms are there in 7.00 moles of aluminum sulfate, $Al_2(SO_4)_3$?

Md Ariful Islam

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In one mole of aluminum sulfate, $"Al"_2"(SO"_4")"_3"$, there are 2 moles Al atoms, 3 moles sulfur atoms, and 12 moles O atoms.

To determine the number of moles of atoms of each element in 7.00 moles of the compound, multiply the number of moles times 7.00.

$"Al":$$7.00cancel("mol Al"_2("SO"_4)_3)xx(2"mol Al atoms")/(1cancel("mol Al"_2("SO"_4)_3))="14.0 mol Al atoms"$

$"S":$$7.00cancel("mol Al"_2("SO"_4)_3)xx(3"mol S atoms")/(1cancel("mol Al"_2("SO"_4)_3))="21.0 mol S atoms"$

$"O":$$7.00cancel("mol Al"_2("SO"_4)_3)xx(12"mol O atoms")/(1cancel("mol Al"_2("SO"_4)_3))="84.0 mol O atoms"$

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