Given: $Na_3N$ decomposes to form sodium (Na) and Nitrogen ($N_2)$ at STP (standard temperature and pressure). At STP $22.4 L = 1$ mole of gas First you need to write...
1 Answers 1 viewsStart by balancing the equation for the reaction between hydrogen $"H"_2$ and nitrogen $"N"_2$, which produces ammonia $"NH"_3$: $color(darkgreen)(1) color(white)(.) "N"_2 (g) + color(darkgreen)(3) color(white)(.) "H"_2 to color(darkgreen)(2) color(white)(.) "NH"_3...
1 Answers 1 viewsSimply, the reaction is $N_2+3H_2=2NH_3$ $140g$ $"N"_2$ means $140/28=5$ mol; $30g$ $H_2$ means $30/2=15$mol From 1 mol of $N_2$ 2 mol $NH_3$ is prepared in perfect presence of $H_2$...
1 Answers 1 viewsYou can actually use two approaches to solve this problem. You can use the to find the number of moles of gas present in that sample, then use...
1 Answers 1 viewsSTP is defined as 1 bar and 0 °C. The molar volume at STP is 22.71 L/mol. $"Moles of Ne" = 36.2 color(red)(cancel(color(black)("g Ne"))) × "1 mol Ne"/(20.18 color(red)(cancel(color(black)("g...
1 Answers 1 viewsSo neon occupies 33.6 g First we find the number of moles of Ne= $(mass)/"molar mass"$ No. of moles= $(33.6)/"20"$ No. of moles= 1.68 mol Then, we can find volume...
1 Answers 1 viewsThe thing to remember about reactions that involve gases held under the same conditions for pressure and temperature is that the mole ratio that exists between the gaseous in the...
1 Answers 1 viewsFirst, write the balanced chemical equation for the equilibrium and set up an ICE table. $color(white)(XXXXXX)"N"_2 color(white)(X)+color(white)(X)"3H"_2 color(white)(l)⇌ color(white)(l)"2NH"_3$ $"I/atm": color(white)(Xll)1.05 color(white)(XXXl)2.02 color(white)(XXXll)0$ $"C/atm": color(white)(X)-x color(white)(XXX)-3x color(white)(XX)+2x$ $"E/atm": color(white)(l)1.05- x...
1 Answers 1 viewsOld $"Dalton's Law of partial pressures"$ tells us that in a gaseous mixture, the exerted by a component gas is the same as the pressure it would exert if it...
1 Answers 1 viewsThis is an example of which states that the volume of a gas held at constant pressure is directly proportional to the Kelvin temperature. The equation for Charles' law is...
1 Answers 1 views