An aqueous solution of
This reaction is commonly used to illustrate basic solubility rules, and solubility equilibria. All nitrates are soluble, hence silver nitrate is soluble; and all halides are soluble, EXCEPT for $AgX$,...
1 Answers 1 views$"2NH"_4"Cl(aq)"+"Pb(NO"_3)_2"(aq)"$$rarr$$"2NH"_4"NO"_3"(aq)"+"PbCl"_2"(s)"$ This is a double replacement reaction, also called a double displacement, metathesis, or precipitation reaction, in which a precipitate (solid) is one of the products. The general equation is...
1 Answers 1 viewsStart by writing the unbalanced chemical equation that describes this double displacement reaction $"FeCl"_ (3(aq)) + "NaOH"_ ((aq)) -> "Fe"("OH")_ (3(s)) darr + "NaCl"$ In order to balance...
1 Answers 1 viewsThe idea here is that each formula unit of aluminium oxide, $"Al"_color(red)(2)"O"_color(blue)(3)$, consists of two aluminium cations, $color(red)(2) xx "Al"^(3+)$ three oxygen anions, $color(blue)(3) xx "O"^(2-)$...
1 Answers 1 viewsThe formula of aluminium fluoride is $"AlF"_3$. This tells us that one formula unit of $"AlF"_3$ contains one atom of $"Al"$ and three atoms of $"F"$. It also...
1 Answers 1 viewsWe need (i) to calculate the molar quantity: $(5.396*g)/(26.982*g*mol^-1)=0.2000*mol$ And then (ii), multiply this molar quantity by $"Avogadro's number"$, $6.022xx10^23*mol^-1$ to get................................... $0.2*molxx6.022xx10^23=??$
1 Answers 1 viewsYour goal here is to figure out exactly how many moles of water of hydration are present for every mole of hydrate. As you can see, the chemical formula of...
1 Answers 1 viewsMoles of $Ag^+$, $(35.0*g)/(169.9*g*mol^(-1)) = ??$ Moles of $Cl^-$, $(25.0*g)/(58.4*g*mol^(-1)) = ??$ The $Na^+(aq)$ and $NO_3^(-)(aq)$ ions are spectators and do not participate in the reaction. Chloride anion is clearly...
1 Answers 1 viewsI'll assume you mean what mass of aluminum hydroxide reacted. We can use the coefficients of the equation to determine the number of moles of $"Al(OH)"_3$ that react, knowing that...
1 Answers 1 viewsIn a saturated solution of a salt in water, there is equilibrium between the solid salt (at the bottom of the flask), and the dissolved salt, present in the homogeneous...
1 Answers 1 views