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The formula of aluminium fluoride is $"AlF"_3$.

This tells us that one formula unit of $"AlF"_3$ contains one atom of $"Al"$ and three atoms of $"F"$.

It also tells us that one mole of contains one mole of $"Al"$ atoms and three moles of $"F"$ atoms.

Thus, we can calculate the molar mass of $"AlF"_3$ as follows:

$"Mass of 1 mol" = 1 color(red)(cancel(color(black)("mol Al"))) × "26.98 g"/(1 color(red)(cancel(color(black)("mol Al")))) + 3 color(red)(cancel(color(black)("mol F"))) × "19.00 g"/(1 color(red)(cancel(color(black)("mol F")))) = "26.98 g + 57.00 g" = "83.98 g"$

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