The coefficients in the equation provide a molar ratio between the chemical species in the equation, so you must first convert the mass of iron (III) oxide to moles of...
1 Answers 1 viewsAnd this is the effectual chemical reaction of our civilization. If you ever have a chance to tour a blast furnace (and most are in China and India now) do...
1 Answers 1 viewsAssume that: n = number of moles m = mass of substance M = molar mass (equivalent to atomic weight on the periodic table) $n = m -: M$...
1 Answers 1 views$n_(Fe_2O_3)=m/(m_r)=40/(2xx55.8+3xx16)=0.25mol$. The balanced chemical equation represents ratio in which chemicals combine. Hence 1 mole iron(III)oxide requires 2 moles aluminium. Therefore by ratio and proportion, $0.25 mol$ iron(III)oxide requires $0.50$ moles...
1 Answers 1 viewsThe given equation takes the following form when balanced $Fe_2O_3+3CO=2Fe+3CO_2$ This equation reveals that 2moles of Fe is produced when 3moles of CO reacts Hence 18 moles of CO can...
1 Answers 1 viewsAs can be seen from the chemical equation, each mole of $Fe_2CO_3$ needs 3 moles of $CO$. If 30 moles of $CO$ are used, only 10 moles of $Fe_2CO_3$ can...
1 Answers 1 views$"Moles of ferric oxide"=(2.112*g)/(159.69*g*mol^-1)$ $=$ $0.0132*mol$ $"Moles of aluminum"=(0.687*g)/(26.98*g*mol^-1)$ $=$ $0.0254*mol$ Aluminum is in slight deficiency, and is thus the . So $0.0254*molxx55.85*g*mol^-1=1.42*g$. I should add that there is a...
1 Answers 1 viewsAssume that: n = number of moles m = mass of substance M = molar mass (equivalent to atomic weight in the periodic table) $n = m -: M$ The...
1 Answers 1 viewsBalanced Equation $"2Fe"_2"O"_3 + "3C"$$rarr$$"4Fe + 3CO"_2$ This is a limiting reactant question. The maximum amount of $"Fe"$ that can be produced is determined by the limiting reactant. We have...
1 Answers 1 viewsYou have the chemical equation, which shows that each mole of ferric oxide should yield 2 moles of iron metal: $Fe_2O_3(s) + 3C(s) rarr 2Fe(l) + 3CO(g)$ $"Moles of iron"$...
1 Answers 1 views