Iron is extracted from iron ore. Part of the process involves reduction of the ore with carbon monoxide. Iron ore contains iron oxide ($Fe_2O_3$). How would you write a balanced equation for the reaction of iron oxide with carbon monoxide?

The coefficients in the equation provide a molar ratio between the chemical species in the equation, so you must first convert the mass of iron (III) oxide to moles of...

Assume that: n = number of moles m = mass of substance M = molar mass (equivalent to atomic weight on the periodic table) $n = m -: M$...

The given equation takes the following form when balanced $Fe_2O_3+3CO=2Fe+3CO_2$ This equation reveals that 2moles of Fe is produced when 3moles of CO reacts Hence 18 moles of CO can...

As can be seen from the chemical equation, each mole of $Fe_2CO_3$ needs 3 moles of $CO$. If 30 moles of $CO$ are used, only 10 moles of $Fe_2CO_3$ can...

$"Moles of ferric oxide"=(2.112*g)/(159.69*g*mol^-1)$ $=$ $0.0132*mol$ $"Moles of aluminum"=(0.687*g)/(26.98*g*mol^-1)$ $=$ $0.0254*mol$ Aluminum is in slight deficiency, and is thus the . So $0.0254*molxx55.85*g*mol^-1=1.42*g$. I should add that there is a...

$"Moles of ferric oxide "=(0.18*g)/(159.69*g*mol^-1)$ $=$ $1.13xx10^-3*mol" metal oxide"$. $"Moles of carbon monoxide "=(0.11*g)/(28.0*g*mol^-1)$ $=$ $3.93xx10^-3*mol" CO"$. $Fe_2O_3$ is the reagent in deficiency (why?), and thus $2xx1.13xx10^-3*molxx55.85*g*mol^-1~=0.150*g$ iron metal are...

Balanced Equation $"2Fe"_2"O"_3 + "3C"$$rarr$$"4Fe + 3CO"_2$ This is a limiting reactant question. The maximum amount of $"Fe"$ that can be produced is determined by the limiting reactant. We have...

$Fe_2O_3(s) + 3CO(g) + Delta rarr 2Fe(l) + 3CO_2(g)uarr$ For each mole of ferric oxide, 3 moles of carbon dioxide are produced. So $"Moles of ferric oxide" = (100*g)/(159.69*g*mol^-1)$...

The answer relates to the stoichiometric equation, which tells us that $159.7*g$ $Fe_2O_3$ reacts with $84.0*g$ $CO$ to give $112*g$ $Fe$. You have $150*"lbs"xx454*g*"lb"^-1$ $=$ $68,100*g$ $Fe_2O_3$. Given the equations...

You have the chemical equation, which shows that each mole of ferric oxide should yield 2 moles of iron metal: $Fe_2O_3(s) + 3C(s) rarr 2Fe(l) + 3CO(g)$ $"Moles of iron"$...