And this is the effectual chemical reaction of our civilization. If you ever have a chance to tour a blast furnace (and most are in China and India now) do...
1 Answers 1 viewsAs can be seen from the chemical equation, each mole of $Fe_2CO_3$ needs 3 moles of $CO$. If 30 moles of $CO$ are used, only 10 moles of $Fe_2CO_3$ can...
1 Answers 1 views$"Moles of ferric oxide "=(0.18*g)/(159.69*g*mol^-1)$ $=$ $1.13xx10^-3*mol" metal oxide"$. $"Moles of carbon monoxide "=(0.11*g)/(28.0*g*mol^-1)$ $=$ $3.93xx10^-3*mol" CO"$. $Fe_2O_3$ is the reagent in deficiency (why?), and thus $2xx1.13xx10^-3*molxx55.85*g*mol^-1~=0.150*g$ iron metal are...
1 Answers 1 viewsBalanced Equation $"2Fe"_2"O"_3 + "3C"$$rarr$$"4Fe + 3CO"_2$ This is a limiting reactant question. The maximum amount of $"Fe"$ that can be produced is determined by the limiting reactant. We have...
1 Answers 1 viewsThe balanced chemical equation tells us unequivocally that 16 g of methane gas reacts with 32 g of dioxygen gas to give 44 g of carbon dioxide, and 36 g...
1 Answers 1 viewsThe answer relates to the stoichiometric equation, which tells us that $159.7*g$ $Fe_2O_3$ reacts with $84.0*g$ $CO$ to give $112*g$ $Fe$. You have $150*"lbs"xx454*g*"lb"^-1$ $=$ $68,100*g$ $Fe_2O_3$. Given the equations...
1 Answers 1 viewsYou have the chemical equation, which shows that each mole of ferric oxide should yield 2 moles of iron metal: $Fe_2O_3(s) + 3C(s) rarr 2Fe(l) + 3CO(g)$ $"Moles of iron"$...
1 Answers 1 viewsThe idea here is that you need to figure out how many moles of carbon dioxide, $"CO"_2$, are initially dissolved in the soda by using the volume and of...
1 Answers 1 viewsEthene undergoes incomplete combustion to form carbon dioxide, carbon monoxide and water vapour. The balanced equation of this incomplete combustion reaction is as follows. $C_2H_4(g)+5/2O_2(g)->CO_2(g)+CO(g)+2H_2O(g)$ But as per question the...
1 Answers 1 viewsThe trick here is to make sure that you do not include the concentrations of the two solids, nickel(II) oxide and nickel metal, in the expression of the equilibrium constant,...
1 Answers 1 views