Now, of course, as chemists we deal with molar quantities, and the oxidation reaction must involve a series of complex elementary steps, but here the molecule is simply represented as
If the amount of Carbon Dioxide released in the process of respiration was greater than the amount of Carbon Dioxide used in the process of the plant would be "starving"...
1 Answers 1 viewsThe relative of carbon is 12.011, which is extremely close to 12.0. This means that the masses C-13, and C-14 are practically negligible when contributing to the relative atomic mass...
1 Answers 1 viewsThis is called the of the element. To make it up to 13 in carbon-13, you will need 7 neutrons. Stable isotopes are not useful at all in radio-dating,...
1 Answers 1 viewsNow carbon dioxide is molecular (and we are exhaling it now!), and the normal Lewis structure is $O=C=O$. The central carbon is $"sp-hybridized"$; the terminal oxygens are $sp^2-"hybridized"$. On t'other...
1 Answers 1 viewsWhen a $3.0*g$ mass of carbon is burnt in an $8.0*g$ mass of dioxygen, the carbon and the oxygen are stoichiometrically equivalent. Of course, the combustion reaction proceeds according to...
1 Answers 1 viewsWe're asked to find the mass of $"CO"_2$ produced in a given reaction, given that $108$ $"g H"_2"O"$ is formed. What we can do first is write the balanced chemical...
1 Answers 1 viewsFrom the reaction clearly 2 moles of lithium salt are required for the removal of 1 mole of carbon dioxide gas. Of course this molar quantity represents a precise mass....
1 Answers 1 views$77.8*g-18.0*g$ oxygen gas reacted, and $22.8*g$ carbon was consumed. Given complete combustion, CLEARLY, $(59.8+22.8)*g=82.6*g$ $CO_2(g)$ were produced. Why $"CLEARLY?"$. Because mass is conserved in all chemical reactions. $"Garbage in must...
1 Answers 1 viewsEthene undergoes incomplete combustion to form carbon dioxide, carbon monoxide and water vapour. The balanced equation of this incomplete combustion reaction is as follows. $C_2H_4(g)+5/2O_2(g)->CO_2(g)+CO(g)+2H_2O(g)$ But as per question the...
1 Answers 1 views$"8.855 g/L"$ This is just asking you to calculate the new molar (i.e. molar solubility) at a different pressure, i.e. use the . (We'll end up converting...
1 Answers 1 views