It is a period or row that is energy level five or more, below calcium on . Two valence electrons places the element in the alkaline earth family or...
The maximum of light that can remove an electron from a lithium atom is equal to $4.279 * 10^(-7)"m"$. So, you know that the work function of lithium, which is...
Phosphorus has $15$. As such its electronic configuration in ground state is $1s^2 2s^2 2p^6 3s^2 3p^3$ The following electronic configurations could be excited states $1s^2 2s^2...
The kinetic energy $("KE")$ of a particle is equal to the difference between its absorbed energy $("AE")$ and its ionization energy $("IE")$. The first ionization energy of $"Hg"$ is $"10.4375...
Given: $1s^2 2s^2 2p^6 3s^1$ can generally be used to find the electron configuration of an element. There are a few special cases: 1st column, hydrogen + alkali metals:...
All I have done here is to use $"the Periodic Table"$, a copy of which you will always have available in every exam in chemistry and physics you will ever...
$Z=11, "sodium"$; the nearest Noble Gas on the Table has $Z=10$. So when sodium is oxidized it should have an equal number of electrons to .......? On the other hand,...
The of metals tend to be lost, and for this reason metals TEND to be reducing. And non-metals are electron poor. And as a result they tend to be oxidizing....
We know that $1*mol$ contains $6.022xx10^23$ individual sodium atoms, and has a mass of $22.99*g$. And thus for $1.$ there is a $2*g$ mass of $Na$. For $2.$ there is...
$%A$ $=$ $(34.5*g)/(34.5*g+18.2*g+2.6*g)xx100%=62.3%$ $%B$ $=$ $(18.2*g)/(34.5*g+18.2*g+2.6*g)xx100%=33.0%$ $%C$ $=$ $(2.6*g)/(34.5*g+18.2*g+2.6*g)xx100%=4.70%$ That is $%" element"$ $=$ $"Mass of element"/"Mass of compound"xx100%$ $"Mass of compound"$ is clearly the SUM of the constituent ....
1 Answers
1 views
Log in to ask questions, provide answers, or leave comments.