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First find the frequency of the photon from the equation

$c=flambda$

$therefore f=c/lambda=(3xx10^8m//s)/(0.050xx10^(-2)m)=6xx10^11Hz$.

Energy of such photons is quantized and given by

$E=hf$

$=(6.6xx10^(-34))(6xx10^11)$

$=3.96xx10^(-22)J$

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