Share with your friends
Call

For carbon dioxide there are $6+6+4=16" valence electrons"$, i.e. 8 electron pairs. There are 2 lone pairs around each oxygen atom, and with the 8 electrons involved in the double bonds, this accounts for the 16 electrons.

For carbon monoxide, there are $6+4=10" valence electrons"$. A representation of $""^+:O-=C:^-$ is typical. This involves formal charge separation, but inorganic chemists tend to like this representation in that carbon monoxide typically coordinates thru the carbon.

Talk Doctor Online in Bissoy App