If the weight of metal chloride is $x$ grams containing $y$ grams of metal, then what is the equivalent weight of the metal in terms of $x$, $y$, and $35.5$?

Md Ariful Islam

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Md Ariful Islam

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For this compound, the equivalent mass of the metal represents the mass of metal that combines with exactly $"35.5 g"$ of chlorine.

You know that the total mass of the oxide is equal to $x$ $"g"$ and that this sample contains $y$ $"g"$ of metal, so you can say that the mass of chlorine present in the sample is equal to

$overbrace(xcolor(white)(.)"g")^(color(blue)("mass of metal chloride")) - overbrace(ycolor(white)(.)"g")^(color(blue)("mass of metal")) = overbrace((x-y)color(white)(.)"g")^(color(blue)("mass of chlorine"))$

So, you know that $y$ $"g"$ of metal combine with $(x-y)$ $"g"$ of chlorine, so you can say that $"35.5 g"$ of chlorine will combine with

$35.5 color(red)(cancel(color(black)("g Cl"))) * (y color(white)(.)"g metal")/((x-y)color(red)(cancel(color(black)("g Cl")))) = (35.5 * y/(x-y))color(white)(.)"g metal"$

Therefore, the equivalent mass of the metal in this compound is equal to

$color(darkgreen)(ul(color(black)("equivalent mass" = (35.5 * y/(x-y))color(white)(.)"g")))$

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