valence(valency, valence number) in the number of valence electron an atom has form, with one or more other valency electron
1 Answers 1 viewsSo for example if they gave us: Ti2+I would write the noble gas electron configuration like this [Ar] 3d2 4s2And then just take away 2 e- from the last number...
1 Answers 1 viewsLet's take a compound NaCl ,The outer shell electronic configuration of Na = [Ne] 2S2 2P0On releasing one electron Na gets a stable noble gas like electronic configurationBut Cl on...
1 Answers 1 viewsSo for example if they gave us: Ti2+I would write the noble gas electron configuration like this [Ar] 3d2 4s2And then just take away 2 e- from the last number...
1 Answers 1 viewsSolution:Sodium + chlorine → sodium chloride The balanced chemical equation:2Na + Cl2 → 2NaClAccording to the equation above: n(Na) = n(NaCl)Moles of Na = Mass of Na / Molar mass of NaThe molar...
1 Answers 1 viewsSolution:The balanced chemical equation:2KBr + Cl2 → 2KCl + Br2According to the equation above: n(Br2) = n(KBr)/2Moles of KBr = Mass of KBr / Molar mass of KBrThe molar mass of...
1 Answers 1 viewsThe equation for this reaction is: Br2 + Cl2 → 2BrCl The number of moles of chlorine gas equals: ν(Cl2) = m(Cl2)/Mr(Cl2) = 26.6 g / (2×35.5 g mol-1) =...
1 Answers 1 viewsAnswer:2HNO3 = 2HNO2 + O2m= 85 x 0.1235 / 69= 0.1521W%= 0.1521 / 0.4230 = 36%
1 Answers 1 viewsm = V×ρm(Br2) = 8.50 mL × 2.91 g/mL = 24.735 gM(Br2) = 159.808 g/moln = m/Mn(Br2) = 24.735 g / 159.808 (g/mol) = 0.154 molOne mole of Br2 molecules...
1 Answers 1 viewsAt first, kilogrammes should be turned into grams:m=80×1000=80000(g).Then, mass should be divided by molar mass:n=m/M=80000/79.9=1001.3(mol).(The data is not very clear. If the point is not mistake, and there are .80...
1 Answers 1 views