1 Answers
Call
Ethanol burns according to the following equation. C2H5OH + 3O2 > 2CO2 +3H2O if 15.0 mole of C2H5OH burns this way, how many moles of oxygen are needed?
21,91 mole
1 Answers 1 views
The density of ethanol is 0.789g/mL. What is the mass of 40.0mL of ethanol?
The mass of ethanol is found according to the equation: m = ρ × V, where ρ – the density and V – the volume. Thus, m = 0.789 g/ml...
1 Answers 1 views
From an initial mix of: 2 mol Cl2, 1 mol Br2, 0.5 mol I2, 0.5 mol Cl−, 1 mol Br−, 2 mol I−; the total quantity of I2 present after all possible reactions occur is
0.5 mol I2 and 0.5 mol Cl- will not react with anything; 2 mol I- will react with one mol of Cl2 producing one mol of I2: 2I- + Cl2...
1 Answers 1 views
A sample of rubbing alcohol solution contains ethanol, C2H5OH(l). If the sample contains 1.25x10^23 atoms of hydrogen in the ethanol, what amount in moles of ethanol is in the sample?
The amount of moles for atom\molecule\compound etc. can be calculated based on amount of atom\molecule\structural units etc. using Avogadro constant (NA=6.02x10^23) that represents 1 mole. One molecule of ethanol consists...
1 Answers 1 views
Beaker A contains a strip of nickel in aluminum sulfate and beaker B contains a strip of aluminum in a solution of nickel sulfate. What happens to each beaker?
According to reactivity series of metals, aluminium is more active. Hence, aluminium will substitute nickel from its salt, while nickel will not substitute aluminium. The answer - nothing will happen...
1 Answers 1 views
Ethanol has a density of 0.789g/mL. What is the mass in mg of 15 gallons of ethanol?
1 gallon= 3.785 L for US or the imperial gallon 1 gallon= 4.54609 L V=15 gallons×3.785 = 56.775 L=56.775×〖10〗^3 ml m=ρ×V=0.789 g/ml×56.775×〖10〗^3 ml≅44.795〖×10〗^3 g=44.795〖×10〗^6 mg Answer Ethanol’s mass must be...
1 Answers 1 views
Find molarity, molality, normality of 12g NaOH per 250ml and density= 1.022g
n(NaOH) = m/M = 12g/40g/mol = 0.3 mol molarity = n(NaOH)/V(solution) = 0.3mol/0.25L = 1.2 mol/L normality = E(NaOH)/V(solution) = 0.3mol/0.25L = 1.2 mol/L m(solution) = 250mL*1.022g/mL = 255.5 g...
1 Answers 1 views
A sample of a wine contain 28% C2H5OH by volume and rest is H2O. Calculate mole fraction of
C2H5OH in wine, density of C2H5OH = 0.79 gm/ml, density of water = 1 gm/ml.
0.28 x 0.79 = 0.22 g.0.22/46 = 0.004 .
1 Answers 1 views
A cough syrup (density 1.25 g/mL) is labelled as containing 16% (v/v) ethanol (density 0.789 g/mL). Express the concentration of the ethanol as percentage (w/w) and as mol/L.
d = m/v => w/w = (1.25 g/mL/ 0.789 g/mL )% = 1.584%Molar mass of ethanol = 46.07 g/molMolar concentration(mol/dm3) = density/molar mass = 0.789 g/mL / 46.07 g/mol = 0.017 * 10-3mol/L
1 Answers 1 views
A student finds that the weight of an empty beaker is 16.600 g. She places a solid in the beaker to give a combined mass of 16.629 g. To how many significant figures is the mass of the solid known?
Solution:16.629 g - 16.600 g = 0.029 gThe mass is known to only 2 significant figures.
1 Answers 1 views