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n(NaOH) = m/M = 12g/40g/mol = 0.3 mol molarity = n(NaOH)/V(solution) = 0.3mol/0.25L = 1.2 mol/L normality = E(NaOH)/V(solution) = 0.3mol/0.25L = 1.2 mol/L m(solution) = 250mL*1.022g/mL = 255.5 g m(H2O) = 255.5 - 12 = 243.5 g molality = 0.3mol/0.2435kg = 1.232 mol/kg
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