If takes 54 ml of 0.1 M NaOH to neutralize 125ml of an HCl solution what is the concentration of HCl
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23.91 mL of a standard solution of KHP of molarity 0.1454M used to standardize a solution of NaOH giving final volume of 26.31 mL of NaOH at endpoint. Calculate concentration of NaOH
0.1321M
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35.6 ± 0.4 mL of 0.600 ± 0.02 M HCl was required to neutralize 35 ± 0.3 mL of a solution of NaOH. Calculate the error in the concentration of NaOH in M from the combined errors in the data.
Concentration of NaOH = Volume of HCl × Concentration of HCl/Volume of NaOHMolar mass of HCl = 36.4580.62 ×36.458/36 = 0.63ml0.63/36.458 = 0.0172mol/0.63 = 0.027mol/L= 0.63 × 0.027/35.3 = 0.0004820.62...
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How many grams of beryllium chloride are needed to make 125mL of a 0.050 M solution
The equation needed to calculate theconcentration is C(M) = n(mol) / V(L) C - concentration (M) n - amount of BeCl2 (mol) V - volume (L) n(mol) = C(M) x...
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If it requires 75.0 mL of 0.500M NaOH to neutralize 165.0 mL of an HCI solution, what is the concentration of the HCI solution?
Solution:Balanced chemical equation:NaOH + HCl → NaCl + H2OAccording to stoichiometry:n(NaOH) = n(HCl)CM(NaOH) × V(NaOH) = CM(HCl) × V(HCl)Therefore,CM(HCl) = CM(NaOH) × V(NaOH) / V(HCl)CM(HCl) = (0.500 M × 75.0...
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If it takes 24.1 mL of a 0.638 M sodium hydroxide solution to neutralize 29.6 mL of a HCl solution, calculate the concentration of the HCl solution.
The balanced equation: NaOH + HCl → NaCl + H2O So, the ratio of reagents is 1:1. Amount of NaOH: 0.638 ∙ 24.1 = 15.3758 mmol Amount of HCl is...
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34.62 mL of a 0.3 M Mg(OH)2 solution are needed to neutralize a 15-mL solution of HCl on unknown concentration. Calculate the concentration of HCl solution.
Mg(OH)2+2HCl=MgCl2+2H2O1.Trace by finding the amount of Mg(OH)2. To do this, we multiply the molarity by the volume (liters): 0.03462litres *0.3 mol/litres= 0.010386 mol Mg(OH)22.based on the reaction we find the amount...
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125ml of 1.00M HCl is added to 100ml of 1.00M NaOH. What is the pH of the resulting solution?
NaOH + HCl --> NaCl + H2OMoles HCl: 1.00M x 0.125L = 0.125 molMoles NaOH: 1.00M x 0.1L = 0.1 mol - limiting reactant because the mole ratio according to...
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To neutralize 25.0mL of a 0.100M solution of HCL requires 40.5 mL of a solution of NaOH. Determine the concentration of the NaOH solution in units of molarity
C1V1=C2V2 at the equivalent pointC(NaOH)=(C(HCl)*V(HCl))/V(NaOH)C(NaOH) = (25 mL * 0.1M)/40.5mL=0.062M
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What is the hydronium-ion concentration in a solution formed by combining 750 mL of 0.10 M NaOH with 250 mL of 0.30 M HCl?
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
We find the moles first(0.75×0.1)mol NaOH +(0.25×0.3)mol HCl0.075 mol NaOH +0.075mol HClO.075mol/L +NaOH+ 0.075mol/L HCl0.075mol/L NaCl appears after the mixingO.075M NaCl---------0.075M Na+ +0.075M Cl-0.075M Na+ +HOH----------no hydrolysis 0.075M Cl- +HOH...
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What mass of NaOH(s) must be added to 300 mL of HCl 0.25 M in order to completely neutralize this acid? 2 HCl + NaOH → NaCl + H<sub>2</sub>O
Solution:The balanced chemical equation:HCl + NaOH → NaCl + H2OAccording to the equation above: n(HCl) = n(NaOH)Molarity of HCl = Moles of HCl / Solution volumeHence,Moles of HCl = n(HCl) = Molarity...
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