What volume of 17.8 M sulphuric acid solution would be needed to make 2.00 L of 0.200 M solution by dilution of the original, concentrated stock solution?

λ CH3COOH = λCH3COONa + λHCl - λNaCl = 91 + 426.16 – 126.45 = 390.71

Molarity =18.4M

110 g/cc is larger than the density of iridium. Certainly you meant 1.10 g/cc. To ease the calculations, take 1 liter of the solution. Its mass is m = V*D...

1.Find graduated cylinder and measure 25 milliliters of stock 2.Find another graduated cylinder or volumetric flask (100.0 mL) 3.Pour previously prepared 25 ml in a volumetric flask (100 ml) 4.Pour...

This is due to the process of acid dissociation. In an 18M solution, the amount of solvent is extremely small, in contrast to 2M, which affects the number of Hydrogen...

Ratio 1:25 means that there have to be 1+25 = 26 equal parts.1) The volume of the original sample needed if we would use a 50 mL volumetric flask is...

If we have 1L of solution, then we have 100 ml (0.1L = 10% from 1L) of sulphuric acid in it. Find the mass of 100 ml of sulphuric acid:...

n(HCl) = 100/1000*15 = 1.5 mol - in final solution, so amount of HCl taken from initial soultion must be the same.V1 = volume of initial solutionV1*18 = 1.5 molV1...

H2SO4 <=> 2H+ + SO42- ;pH=-lg[H+] ;[H+]=10^(-pH)=10-2=0.01;[H2SO4]=[H+]/2=0.01/2=0.005 mol/L;Answer: the molarity of sulphuric acid is 0.005 M;

24cm of 0.2M sodium hydroxide was used to tritrate against 20cm of sulphuric acid.So, V = 24cm, S = 0.2 M V' = 20cm , S' = ? Hence, VS=V'S'...