С = 4.184 J/(g*C) delta T = 9 C for m = 1 and delta t=9 it is 4.184*9=37.656 j for m=x and delta t =9 it is 1367/37.656 =...
1 Answers 1 viewsUsing law PV = nRT, you can see, that if n,R = const, and T and P are used for some processes,V-volume is the one,that can be changed.
1 Answers 1 viewsThis question can be solved using the ideal gas law: PV = nRT P is pressure V is volume n is amount R is gas constant = 8.31 T is...
1 Answers 1 viewsdelta E=0 delta H = Cp delta T delta U = Cv delta T + p delta V q = delta H w = p delta V delta U =...
1 Answers 1 viewsAccording to the ideal gas equation:P1V1/T1 = P2V2/T2,where P1, V1, T2 - initial pressure, volume and temperature, P2, V2, T2 - pressure, volume and temperatureAs a result:V2 = P1V1T2 /...
1 Answers 1 viewsThe melting temperature depends on the strength of the crystal lattice, forms. When the kinetic energy of the vibrational motion of the crystal lattice sites converts the energy, the metal...
1 Answers 1 viewsSolubility here is the amount of solute that is needed in order to reach saturated solution. If temperature remains constant then amount of solute is proportional to the amount of...
1 Answers 1 viewsQ=c*m*(t2-t1); c=Q/[m*(t2-t1)]=133 cal/[0.25 kg*(40.1-23.0)C]=31.1 cal/(kg*C)
1 Answers 1 viewsq = cmΔT => c = q / mΔT = 112300J / (240g x (880oC - 13oC)) = 0.54 J/goCAnswer: c = 0.54 J/goC
1 Answers 1 viewsAccording to Newton's law of cooling, mc(T1 - T2)/t = k [(T1 +T2)/2 - T0)] ---------------(1) mc/k = [(T1 +T2)/2 - T0)]/[(T1 - T2)/t] mc/k= [(140+80)/2 - 35)]/[(140 -80)/25] =75/2.4 SubstitutingT1 = 140 and T2 = 80 and T0 = 25 (all in °C) in Eq. (1),weget mc (140 - 80)/t = k [(140+...
1 Answers 1 views