In the case of Silicon dioxide, two different types of bonding is present. It is because, in it, each silicon atom is bonded with four oxygen atoms and each oxygen...
1 Answers 1 viewsΔH = 600 J/molT = 273 Kwe know, S= ΔH/TS = 600 Jmol-1/273 K = 2.19 Jmol-1k-1 Hence,the standard entropy of melting of ice is 2.19 Jmol-1k-1
1 Answers 1 viewsSharp melting point is characteristic to pure substances and reason of some melting range is impurity. in General in our world there are not a lot of 100% pure substances....
1 Answers 1 viewsBoiling Point =246 °CDensity =1.183 g/cm3Appearance=White or cream crystalline powderMelting Point =114-116 °CYes
1 Answers 1 viewsA small amount of impurity decreases melting point an organic compound
1 Answers 1 viewsQ=ΔHfus·n n=m/M M (NH3)=17 g/mol m (NH3)=(Q·M)/ΔHfus m (NH3)=(3.5·17)/5.66=10.5 g
1 Answers 1 viewsMollar mass (C6H6) = 78 g/mol n = 7.87 / 78 = 0.101 (mol) Q = 0.101 * 9.92 = 1.002 (kJ)
1 Answers 1 viewsΔH = 600Jmol-1 T = 2730K S - ? S = ΔH/T S = 600Jmol-1/2730K = 2,20 Jmol-1K-1
1 Answers 1 viewsdelta T = i•Kf•molalityMolality = moles / kg solventYou have molality and kg solvent, solve for moles.Moles = grams / molar mass. You have moles and grams, solve for molar...
1 Answers 1 viewsTemperature T=327OC=600K Heat, q=600×5.28kJ Entropy change, ΔS=K 600×5.8kJ=3480KJ(3480)/(6.023)(1023) = 5.778-21
1 Answers 1 views