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1. If there are 42 g of Hydrogen in a sample of pure Methane (CH4), how many grams of Carbon are present? Show how these data illustrate the law of definite proportions.
Grams of Carbon =126g
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ron metal is produced in a blast furnace by the reaction of iron (III) oxide and coke (pure carbon). If 25.0 moles of pure Fe2O3 is used, how many grams of iron can be produced?
Solution: n(Fe2O3)=25.0mol n(Fe0)-? 1. For calculation n(Fe) we need to calculate m(Fe2O3): Mr(Fe2O3)=55.85*2+16*3=159.6(g/mol) n=m/Mr; hereof m(Fe2O3)=n*Mr=159.6(g/mol)*25mol=3990g 2. Compose proportion: 3990(g) it is 159.6 X(g) it is 55.85*2 Where X is the total...
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A 49.50 g sample of a substance is initially at 20.7 °C. After absorbing 1633 J of heat, the temperature of the substance is 154.8 °C. What is the specific heat (c) of the substance?
c = Q / m * ∆T ∆T = T2 – T1 T2 = t2 + 273.15 = 154.8 °C+ 273.15 = 427.95 K T1 = t1 + 273.15 =...
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A solid, pure substance containing just carbon and hydrogen is found to contain 23.6g of carbon and 3.45 g of hydrogen. How many grams of carbon will be in a 6.45 g sample of the solid?
Solid sample is - carbon (23,6g) + hydrogen (3,45g) = 27,05g (100%) Carbon content in substance (%) is : 23,6/27,05 = 0,8725 * 100%= 87,25% In 6,45g solid sample will...
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A compound containing only carbon and hydrogen is found to contain 4.1315 g of carbon and 0.8685 g of hydrogen. Determine the empirical formula of hydrocarbon
CxHy w(C) = 4.1315 g / (4.1315 g + 0.8685 g) = 0.8263 w(H) = 0.8685 g / (4.1315 g + 0.8685 g) = 0.1737 x : y = 0.8263/12,0107...
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If there are 42 grams of hydrogen in a sample of pure methane, how much grams of carbon are present?
CH4 12------4X--------42X= 42 x 12/4= 126 g of carbon
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If 10 grams of iron contain 'y' atoms, how many grams of aluminum will contain 'y' atoms.
Molecular weight of iron 55.84 gm10 gm contain 0.179 mol of iron same number of moles contain same number of atom irrespective of identity of atom0.179 mol of Aluminium will...
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a sample of pure acetic acid CH3COOH contains 1.40 x 10^23 carbon atoms. How many grams of acetic acid are in the sample?
Solution.n(C) = 0.232 molesn (CH3COOH) = 0.116 molesm (CH3COOH) = 0.116*60 = 6.97 gAnswer. 6.97 g
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A substance contains 35.0 g nitrogen, 5.05 g hydrogen, and 60.0 g of oxygen. How many grams of hydrogen are there in a 137-g sample of this substance?
35g N, 5.05g h, 60.0g 02..5.05÷100.05=0.05047476260.005047...x137=6.9156.915g of hydrogen in 137 g sample
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If there are 76 g of Hydrogen in a sample of pure methane (CH4), how many grams of Carbon are present?
Solution:76g / 1g/mol=76 mol of H476mol / 4 = 19 mol of C19 mol * 12 g/mol=228g of CAnswer:228 grams.
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